How Do Ships A and B Move Relative to Each Other?

AI Thread Summary
Two ships, A and B, depart simultaneously, with ship A traveling northwest at 22 knots and ship B moving at 29 knots, 40° west of south. The discussion focuses on calculating the relative velocity of ship A with respect to ship B, including its magnitude and direction. The user attempts to resolve vector components but struggles with the correct application of vector addition and the angles involved. A key point raised is the confusion between the directions of the ships and the need to correctly interpret "west of south." The conversation emphasizes the importance of accurately determining vector components to solve the problem effectively.
Jharr94
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Homework Statement


Two ships, A and B, leave port at the same time. Ship A travels northwest at 22 knots and ship B travels at 29 knots in a direction 40° west of south.

(a) What is the magnitude the velocity of ship A relative to B?

(b) What is the direction of the velocity of ship A relative to B?

(c) After what time will the ships be 125 nautical miles apart?

(d) What will be the bearing of B (the direction of B's position) relative to A at that time?



Homework Equations



V_aw=V_ab+V_b Where a is boat a, b is boat b, and w is the water-also aw is ship a's velocity with respect to the water, ab is the velocity of a with respect to b)




The Attempt at a Solution


I found the componets of the two vectors(with respect to a y-axis that's positive in the north direction and an x-axis positive in the east direction) as:
A=(-15.55i+15.55j) or (22cos45+22sin45)
B=(-22.22i+-18.64j) or (29cos40+29sin40)

I've found these componets with respect to their own frames of reference, however the problems asks for the magnitude of the velocity of a with respect to b, so should I measure my angles of a from the b vector? I'm lost as to how to solve. Also I've come to the conclusion that this is addition( or subtraction) of vectors a and b, being that its a with respect to b however I'm not sure if it is B-A=C (with c being the velocity of a with respect to b)or A-B=C.
 
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So I'm looking for V_ab( velocity of a with respect to b), therefore the velocity of a(V_a) is equal to the velocity of b(V_B) plus the velocity of a with respect to b(V_ab) and I know both a and b so:

V_a=V_ab+V_b

22=V_ab+29

-7=V_ab

however is is showing as incorrect(I used 7 since it asked for the magnitude)
 
I also tried the vector equations:

(V_ax+V_ay)=(V_abx+V_aby)+(V_bx+V_by)

or

(-15.55i+15.55j)=(V_abx+V_aby)+(-22.22i+18.64j)

so when I separate the equations I get:

-15.55=V_abx-22.22

V_abx=6.67i

15.55=V_aby+18.64

V_aby=-3.09

therefore V_ab=(6.67i+3.09j)
so the magnitude of V_ab should be 7.35
Right?
 
I really need help with this, its due in a few hours. =/
 
Welcome to PF!

Jharr94 said:
Two ships, A and B, leave port at the same time. Ship A travels northwest at 22 knots and ship B travels at 29 knots in a direction 40° west of south.

B=(-22.22i+-18.64j) or (29cos40+29sin40)

Hi Jharr94! Welcome to PF! :smile:

West of south is between southwest and south.

You're using south of west. :cry:
 
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