How Do T and V Relate in Adiabatic Processes for Different Substances?

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In adiabatic processes involving black body radiation, the energy E and pressure p are related to temperature T and volume V through the equations E = σV T^4 and p = (1/3)σT^4. When temperature and volume change adiabatically, the relationship between dE and dT can be established, leading to the conclusion that T is proportional to V raised to the power of -1/3. For a pressureless substance, described by E = γV T^(2/3) and p = 0, the relationship between T and V during adiabatic changes needs to be determined as well. The discussion highlights confusion regarding the derivation of these relationships and the proper assembly of the equations. Understanding these principles is crucial for solving the problems related to adiabatic processes.
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Homework Statement


[/B]
a) Black body radiation:

The energy and pressure of black body radiation depend on T and V as E = σV T^4 , p=\frac{1}{3}σT^4 σ = a constant

(1) Suppose that the temperature and volume of a box of radiation change adiabatically, which means that there is no heat flow. First, find the relation between dE and dT in this process. Next using equation (1) show that T ∝ V^-\frac{1}{3}

b)Pressureless glop

Suppose that the energy and pressure of a different substance are given by E = γV T^\frac{2}{3} ,p = 0 γ = constant

The temperature and volume of a box of this substance are changed adiabatically. What is the relation between T and V during this process?

Homework Equations


See problem description

The Attempt at a Solution


I'm not quite sure where to begin with this one. I've solved every other problem in the problem set without a problem, but this one I'm a little confused where to start.

\Delta E = Q - W

The processes are adiabatic, so Q = 0. Also, W = pdV

Therefore
\Delta E = -pdV

Is it asking me to find dE/dT? For part a this would be:
\frac{dE}{dT} = 4σVT^3

After I get these pieces, I'm not sure how to assemble them into the answers the problems are asking for.
 
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RadiumBlue said:
##\frac{dE}{dT} = 4σVT^3##
That would only be true if V is constant with respect to changes in T. Is it?
 
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