How do the dots in inductor circuits indicate polarity and current direction?

AI Thread Summary
In inductor circuits, the dots indicate polarity and current direction, with their placement reflecting the relationship between voltage and current. The discussion centers on a setup with two inductors where the current (i1) is a triangular wave and the voltage (v2) is a step wave. It is noted that the voltage is the derivative of the current, suggesting a negative sign in their relationship. The correct placement of the dots should be on opposite sides to accurately represent this relationship. The original question is resolved with an understanding of the dot convention in inductors.
EvLer
Messages
454
Reaction score
0
one more electro-magnetic question:
here's the set-up: two inductors, the A-B has a signal source hooked-up, C-D is open circuit.
Code:
->i1
A       C 
)    (    +
)    (    V2
)    (    -
B       D

i1 is given as a triangular wave, v2 as a step wave for:
0 < t < 0.5, i1 has negative slope below t-axis, v2=4;
0.5<t<1, i1 has positive slope below t-axis, v2 = -4;
1<t<1.5, i1 has positive slope above t-axis, v2 = 0

so, i clearly see that voltage is derivative of current and there is a negative sign involved, so the dots are placed diagonally?
If not, could you explain that as well?
Thanks in advance...
 
Physics news on Phys.org
solved

well... yeah, they should be on the opposite side, i think i got the idea...
 

Similar threads

Replies
26
Views
3K
Replies
1
Views
3K
Replies
3
Views
2K
Replies
7
Views
4K
Back
Top