dcgirl16 Messages 27 Reaction score 0 Thread starter Mar 27, 2006 #1 how do u find the height of an object thrown straight up if u are only given that it is thrown with a velocity of 30m/s
how do u find the height of an object thrown straight up if u are only given that it is thrown with a velocity of 30m/s
arildno Science Advisor Homework Helper Gold Member Dearly Missed Messages 10,165 Reaction score 138 Mar 27, 2006 #2 Energy conservation..
arildno Science Advisor Homework Helper Gold Member Dearly Missed Messages 10,165 Reaction score 138 Mar 27, 2006 #4 Write down the equation for energy conservation, perhaps?
daniel_i_l Gold Member Messages 864 Reaction score 0 Mar 27, 2006 #6 What is the initial kinetic energy? If that energy is turned to potential energy, how high is the object?
What is the initial kinetic energy? If that energy is turned to potential energy, how high is the object?
ThomasW Messages 2 Reaction score 0 Mar 27, 2006 #7 because energy is conserved, all the kinetic energy will be converted to potential energy KE = PE 1/2 mv^2 = mgh 1/2 v^2 = gh 1/2 (30)^2 = 9.8 h
because energy is conserved, all the kinetic energy will be converted to potential energy KE = PE 1/2 mv^2 = mgh 1/2 v^2 = gh 1/2 (30)^2 = 9.8 h
arildno Science Advisor Homework Helper Gold Member Dearly Missed Messages 10,165 Reaction score 138 Mar 27, 2006 #8 ThomasW: Let the original poster try to solve the problem on her own before providing a full solution. Welcome to PF, by the way.
ThomasW: Let the original poster try to solve the problem on her own before providing a full solution. Welcome to PF, by the way.
benzun_1999 Messages 260 Reaction score 0 Mar 28, 2006 #10 u can also use equations of motion ie is v^2=u^2+2gs where v is final velocity here it is 0, where u is initial velocity(given) where g is acceleration due to gravity where s is the distance or height reached.
u can also use equations of motion ie is v^2=u^2+2gs where v is final velocity here it is 0, where u is initial velocity(given) where g is acceleration due to gravity where s is the distance or height reached.