How do u find the height of an object thrown straight up

  • Thread starter dcgirl16
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In summary, to find the height of an object thrown straight up with a velocity of 30m/s, you can use the equation for energy conservation (KE = PE) or the equation of motion (v^2 = u^2 + 2gs). By setting the final velocity to 0 and solving for height, you can determine the height reached by the object.
  • #1
dcgirl16
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how do u find the height of an object thrown straight up if u are only given that it is thrown with a velocity of 30m/s
 
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  • #2
Energy conservation..
 
  • #3
so how do i do it
 
  • #4
Write down the equation for energy conservation, perhaps?
 
  • #5
how exactly is the question worded?
 
  • #6
What is the initial kinetic energy? If that energy is turned to potential energy, how high is the object?
 
  • #7
because energy is conserved, all the kinetic energy will be converted to potential energy
KE = PE
1/2 mv^2 = mgh
1/2 v^2 = gh
1/2 (30)^2 = 9.8 h
 
  • #8
ThomasW:
Let the original poster try to solve the problem on her own before providing a full solution.

Welcome to PF, by the way.
 
  • #9
alrite, arildno
i'll do that from now on
 
  • #10
u can also use equations of motion
ie is v^2=u^2+2gs
where v is final velocity here it is 0,
where u is initial velocity(given)
where g is acceleration due to gravity
where s is the distance or height reached.
 

1. How do you measure the height of an object thrown straight up?

To find the height of an object thrown straight up, you can use the formula h = v2 / 2g, where h is the height, v is the initial velocity, and g is the acceleration due to gravity. You will need to measure the initial velocity and use a timer to determine the time it takes for the object to reach its highest point.

2. Can you use a ruler to measure the height of an object thrown straight up?

No, a ruler will not be accurate for measuring the height of an object thrown straight up. This is because the object reaches its highest point in a very short period of time and the ruler may not be able to capture the exact height. It is recommended to use a timer and the appropriate formula to calculate the height.

3. How does air resistance affect the measurement of an object's height when thrown straight up?

Air resistance can affect the measurement of an object's height when thrown straight up. The object may not reach its maximum height due to the force of air resistance pushing against it. This can result in an inaccurate measurement of the height. In order to minimize the effect of air resistance, it is recommended to perform the experiment in a vacuum or to use a small and dense object.

4. Can the height of an object thrown straight up be negative?

Yes, the height of an object thrown straight up can be negative. This occurs when the object is thrown from a higher elevation and does not reach the ground before it starts to fall back down. In this case, the initial height is taken as the reference point and any height above it is considered positive, while any height below it is considered negative.

5. Is the height of an object thrown straight up affected by the mass of the object?

Yes, the height of an object thrown straight up is affected by the mass of the object. According to the formula h = v2 / 2g, the height is directly proportional to the initial velocity and inversely proportional to the acceleration due to gravity. Since the mass of an object affects both the initial velocity and the acceleration due to gravity, it will also affect the height reached by the object.

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