How do u find the height of an object thrown straight up

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how do u find the height of an object thrown straight up if u are only given that it is thrown with a velocity of 30m/s
 
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Write down the equation for energy conservation, perhaps?
 
What is the initial kinetic energy? If that energy is turned to potential energy, how high is the object?
 
because energy is conserved, all the kinetic energy will be converted to potential energy
KE = PE
1/2 mv^2 = mgh
1/2 v^2 = gh
1/2 (30)^2 = 9.8 h
 
ThomasW:
Let the original poster try to solve the problem on her own before providing a full solution.

Welcome to PF, by the way.
 
u can also use equations of motion
ie is v^2=u^2+2gs
where v is final velocity here it is 0,
where u is initial velocity(given)
where g is acceleration due to gravity
where s is the distance or height reached.