How do u find the height of an object thrown straight up

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Homework Help Overview

The discussion revolves around finding the height of an object thrown straight up with an initial velocity of 30 m/s, focusing on the principles of energy conservation and equations of motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore energy conservation principles, questioning how kinetic energy converts to potential energy. Others suggest using equations of motion to analyze the problem further.

Discussion Status

Participants have provided various approaches, including energy conservation equations and motion equations, while encouraging the original poster to engage in problem-solving independently. There is an acknowledgment of different methods being discussed without reaching a consensus.

Contextual Notes

Some participants question the wording of the original problem and the assumptions regarding energy conservation and motion equations.

dcgirl16
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how do u find the height of an object thrown straight up if u are only given that it is thrown with a velocity of 30m/s
 
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Energy conservation..
 
so how do i do it
 
Write down the equation for energy conservation, perhaps?
 
how exactly is the question worded?
 
What is the initial kinetic energy? If that energy is turned to potential energy, how high is the object?
 
because energy is conserved, all the kinetic energy will be converted to potential energy
KE = PE
1/2 mv^2 = mgh
1/2 v^2 = gh
1/2 (30)^2 = 9.8 h
 
ThomasW:
Let the original poster try to solve the problem on her own before providing a full solution.

Welcome to PF, by the way.
 
alrite, arildno
i'll do that from now on
 
  • #10
u can also use equations of motion
ie is v^2=u^2+2gs
where v is final velocity here it is 0,
where u is initial velocity(given)
where g is acceleration due to gravity
where s is the distance or height reached.
 

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