How do u find the height of an object thrown straight up

  • Thread starter dcgirl16
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  • #1
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how do u find the height of an object thrown straight up if u are only given that it is thrown with a velocity of 30m/s
 

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  • #2
arildno
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Energy conservation..
 
  • #3
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so how do i do it
 
  • #4
arildno
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Write down the equation for energy conservation, perhaps?
 
  • #5
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how exactly is the question worded?
 
  • #6
daniel_i_l
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What is the initial kinetic energy? If that energy is turned to potential energy, how high is the object?
 
  • #7
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because energy is conserved, all the kinetic energy will be converted to potential energy
KE = PE
1/2 mv^2 = mgh
1/2 v^2 = gh
1/2 (30)^2 = 9.8 h
 
  • #8
arildno
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ThomasW:
Let the original poster try to solve the problem on her own before providing a full solution.

Welcome to PF, by the way.
 
  • #9
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alrite, arildno
i'll do that from now on
 
  • #10
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u can also use equations of motion
ie is v^2=u^2+2gs
where v is final velocity here it is 0,
where u is initial velocity(given)
where g is acceleration due to gravity
where s is the distance or height reached.
 

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