How Do Velocity and Acceleration Relate in Circular Motion?

AI Thread Summary
In circular motion, the relationship between velocity and acceleration is crucial, especially when speed varies over time. The problem involves a racing car with speed expressed as v = kt, where k is a constant, and requires showing that the angle between the velocity and acceleration vectors is 45 degrees at a specific time. To solve this, one must differentiate the position equation to find both the tangential and radial components of velocity and acceleration. By using the dot product of the velocity and acceleration vectors, the condition for the angle to be 45 degrees can be derived. Ultimately, the solution hinges on determining the correct time t, which is found to be t = (a/k)^(1/2).
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velocity & acceleration PLZZZZ HELP ME!

:eek: hi i have this question from fowles anlaytical mechanics.It says

A racing car moves along a circular track of radius 'a'.The speed of the car varies with time as v=kt where k is a poistive constant.Show that the angle between the velocity vector and acceleration vector is 45 degrees when t= (a/k)^1/2

i took the equation of motion to be r= a cos[(kt^2)/a]+a sin[(kt^2)/a]
then differentiated to get velocity and acceleration...i represented a particular portion of each velocity and acceleration as a unit vector p and q so as to reduce the size of the equations.HOwever when i try to calculate the angle between a and v..at that time..it doesn't come out to be 45..Can ne one please help ,me!
 
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You can determine both the tangential and radial (centripetal) components of velocity and acceleration at any instant. Make it easy on yourself and choose your coordinates for a given instant of time to be such that the tangential direction is, say, in the postitive y direction and the radial component in the x direction.

Then note that \vec v \cdot \vec a = v a \cos \theta and you can explicitly evaluate the dot product since you know the components of each vector. What must t be in order for \theta to be 45 degrees?
 
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