How do we get the second matrix from the first one in this example

  • Thread starter Thread starter Madou
  • Start date Start date
  • Tags Tags
    Example Matrix
Click For Summary

Homework Help Overview

The discussion revolves around understanding how to derive a second block matrix from a given first matrix using elementary row operations. The matrices involved contain fractions and represent a specific structure that participants are trying to manipulate.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants express confusion about the transformation of the first matrix into the second and seek clarification on the elementary row operations required. There are attempts to rewrite the matrices in LaTeX format for clarity, and questions arise regarding the proper formatting for posting matrices in the forum.

Discussion Status

Some participants are exploring different interpretations of the matrices and the operations involved. There is a recognition of the need to clarify how the first row of the first matrix changes and how this relates to the subsequent matrices. Guidance has been offered regarding the use of LaTeX for matrix representation.

Contextual Notes

Participants are navigating the complexities of matrix operations while adhering to forum rules about posting and formatting. There is a mention of specific rows and operations that may not be fully resolved, indicating ongoing exploration of the topic.

Madou
Messages
42
Reaction score
0

Homework Statement


I have a matrix 1, 0, 1/12, 1/12 | 1/12, 0, 0, 0
0, 12, 143/12, 11/12 |-1/12, 1, 0, 0
0, 12, 143/12, 11/12 |-13/12,0,1,0
0, -12, -143/12, -11/12|-11/12,0,0,1
---------------------------------------------------
1 , 0, 0 , 0 |
0, 1, 0 , 0 |
0, 0, 1, 0 |
0, 0, 0 , 1 |
And I can't understand how can one get the following block matrix from the previous one with elementary row operations:
1, 0, 1/12, 1/12 | 1/12, 0, 0, 0
0, 12, 143/12, 11/12 |-1/12, 1, 0, 0
0, 12, 143/12, 11/12 |-13/12,0,1,0
0, -12, -143/12, -11/12|-11/12,0,0,1
---------------------------------------------------
1 , 0, -1/12 ,-1/12 |
0, 1, 0 , 0 |
0, 0, 1, 0 |
0, 0, 0 , 1 |

And ideas?



Homework Equations





The Attempt at a Solution



 
Physics news on Phys.org
I have a matrix:
1, 0, 1/12, 1/12 | 1/12, 0, 0, 0
0, 12, 143/12, 11/12 |-1/12, 1, 0, 0
0, 12, 143/12, 11/12 |-13/12,0,1,0
0, -12, -143/12, -11/12|-11/12,0,0,1
---------------------------------------------------
1 , 0, 0 , 0 |
0, 1, 0 , 0 |
0, 0, 1, 0 |
0, 0, 0 , 1 |
And I can't understand how can one get the following block matrix from the previous one with elementary row operations:
1, 0, 1/12, 1/12 | 1/12, 0, 0, 0
0, 12, 143/12, 11/12 |-1/12, 1, 0, 0
0, 12, 143/12, 11/12 |-13/12,0,1,0
0, -12, -143/12, -11/12|-11/12,0,0,1
---------------------------------------------------
1 , 0, -1/12 ,-1/12 |
0, 1, 0 , 0 |
0, 0, 1, 0 |
0, 0, 0 , 1 |

And ideas?
 
That's a bit confusing. I see what looks like three matrices. Can you rewrite it using the latex array format? Example: \begin{array}{ccc} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{array} gives:

[tex]\begin{array}{ccc} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{array}[/tex]
 
And how do I put this ( \begin{array}{ccc} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{array}) into a message (reply to thread)?
 
Use the tex delimiters. Just click on the matrix in my post, you should get a popup with the source code.
 
Could you please say where are the TEX delimeters?
 
You type them [x] \begin{array}{ccc} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{array} [/x] where x=tex. Use cccc for a 4x4 matrix instead of ccc.
 
ok i think i see now how to type it
 
[tex]Matrix A: \begin{array}{cccc} 1 & 0 & 1/12 & 1/12 \\ 0 & 12 & 143/12 & 11/12\\ 0 & 12& 143/12 & 11/12 \\ 0 & -12 & -143/12 & -11/12\end{array} <br /> Matrix B : \begin{array}{cccc} 1/12 & 0 & 0 & 0 \\ -1/12 & 1 & 0 & 0\\ -13/12 & 0& 1 & 0 \\ -11/12 & 0 & 0 & 1\end{array}<br /> Matrix C : \begin{array}{cccc} 1 & 0 & 0 & 0 \\ 0 & 1 & 0 & 0\\ 0 & 0& 1 & 0 \\ 0 & 0 & 0 & 1\end{array}[/tex]
They are located this way in a block matrix :
AB
CAnd how can I get this with elementary row operations?

[tex]Matrix A: \begin{array}{cccc} 1 & 0 & 0 & 0\\ 0 & 12 & 143/12 & 11/12\\ 0 & 12& 143/12 & 11/12 \\ 0 & -12 & -143/12 & -11/12\end{array} <br /> Matrix B : \begin{array}{cccc} 1/12 & 0 & 0 & 0 \\ -1/12 & 1 & 0 & 0\\ -13/12 & 0& 1 & 0 \\ -11/12 & 0 & 0 & 1\end{array}<br /> Matrix C : \begin{array}{cccc} 1 & 0 &-1/12 & -1/12 \\ 0 & 1 & 0 & 0\\ 0 & 0& 1 & 0 \\ 0 & 0 & 0 & 1\end{array}[/tex]
So I have a new matrix

AB
C
 
  • #10
Forget about A and B. You can do the operations on C alone. Look at rows 7 and 8.
 
  • #11
hmm... I see what you mean. But the thing is I thought in this example I was doing things with matrix A and matrices B and C were the 'reflections' of what I was doing with matrix A.
And what about the first row in matrix A? You see it has changed also.
 
Last edited:
  • #12
ohh, I think I see now the answer to my question.

I can now add the 7th row multiplyed by -1/12 and the 8th multiplyed by -1/12 to the first one and I GET WHAT I SEE! ;)
 
  • #13
but this way C is not a 'reflection'...
 
  • #14
I see. In your original question, A's first row was unchanged. In that case, just use the new C row to get the result.
 
  • #15
thank you very much, cellotim
 
  • #16
Hi Madou! Welcome to PF! :smile:

Hi cellotim! (are we related?:wink:)

There's an easier way to do matrices: use the CODE tag (next to the QUOTE tag)…

it's really intended for writing computer code, but it does matrices nicely, because it prints with equal spacing, as on a typewriter …

Code:
1    0    1/12   1/12
0   12  143/12  11/12
0   12  143/12  11/12
0   12 -143/12 -11/12
 

Similar threads

Replies
6
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 30 ·
2
Replies
30
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K