How Do You Analyze the Function f(x) = ax + (b/x) for Extrema and Concavity?

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Homework Statement



4) Let f(x)= ax+(b/x) where a and b are positive constants.
(a) Find in terms of a and b, the intervals on which f is increasing.
(b) Find the coordinates of all local maximum and minimum points.
(c) On what interval(s) is the graph concave up?
(d) Find any inflection points. Explain your answer.

The Attempt at a Solution



I need to take the derivative so it is f'(x)= a-b(x^-2) then I set this equal to zero to find the critical points, but then I'm not sure what value to solve for. X? If I do that I get critical points at +/- \sqrt{}b/a
 
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If you set a- bx-1 equal to 0, the only thing left to solve for is x! Yes, x= \sqrt{b/a} and x= -\sqrt{b/a} are the critical values of x. What does that tell you about a, b, c, and d?
 
so is the function increasing from (-infinity,-root(b/a)) union (root(b/a),infinity)? Then should I take the second derivative set it equal to zero to find the inflection point
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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