How Do You Apply Linear Transformations to Find T(-3, 4)?

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Homework Statement


Let u = (1,2), v = (3,1) and T: R^{2}\rightarrow R be a linear transformation such that T(u)= 4 and T(v)= 5. What is T(-3, 4)? (Hint: Write (-3,4) as a linear combination of u and v.)


Homework Equations


T(x)= b


The Attempt at a Solution


I don't really know where to start. I know I have to write (-3,4) as a linear combination of u and v, but what do I do from there?
 
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The vectors u and v form a basis for R^2, since they're linearly independent (and there is two of them). So, you can write any vector in R^2 as their linear combination, with some coefficients α, β, so, for xome vector x (in your case (-3, 4) ), you have x = α u + β v. Now, what does T(x) equal to?
 
So I determined α = 3 and β = -2 using your method. I was then able to solve for T(-3,4) = 2.

Is this correct?
 
Yes, it is correct.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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