How Do You Balance Forces in a Charged Rhombus?

AI Thread Summary
To balance the forces in the charged rhombus, the charge q at vertex D must create an electric field that counteracts the forces from the charges at vertices A and C on the charge -Q at vertex B. The required size of charge q can be determined by analyzing the force vectors acting on the charge at B, ensuring that the net force equals zero. If charge q is removed, the initial acceleration of the particle at B can be calculated using Coulomb's law and Newton's second law, considering the forces from charges at A and C. The velocity of the particle upon reaching the center of the rhombus can be derived from its initial acceleration and the distance traveled. Understanding these principles is crucial for solving the problem effectively.
kokoman
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Hello, please help me solve this so I can learn from it.

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Two charges with charge +Q are placed at A and C vertices of a rhombus with four even sides (α).
A prticle with mass m and charge -Q is placed at vertex B.
An unknown charge size of q is placed at vertex D.
The sharp angle of the rhombus is 60 degrees.

1)
What is the size of charge q, that is suffiecient to make the electrical charge affecting the -Q charged particle at vertex B to be 0?

If charge q is removed, and the particle at vertex B is released from being stationary, while the charges at vertice A and C are still held in place.
2)
What is the initial acceleration of the released particle?
3)
What is the velocity of the particle upon reaching the center of the rhombus?

I have no much of an attempt at solution for I'm am unsure of where to start.

Thank you very much!
 
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For (1) start by drawing all the force vectors acting on the charge at B and adding them.
 
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