How Do You Calculate Charge and Radius from Maximum Potential?

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To calculate the charge and radius of a spherical conductor from a maximum potential of 580 kV, the equation V = kq/r is used, where V is the potential, k is a constant (8.99x10^9 N*m²/C²), q is the charge, and r is the radius. By rearranging the equation to solve for charge, q = V*r/k, the charge can be determined as q = 580 kV * r / 8.99x10^9 N*m²/C². Subsequently, the radius can be calculated using r = kq/V, leading to r = 580 kV when substituting the known values. Ultimately, both the charge and radius of the spherical conductor are found to be 580 kV. This method effectively demonstrates the relationship between charge, radius, and potential in electrostatics.
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Homework Statement


This should be really easy, but I can't think right now so...We have a maximum potential of 580 kV. Now we need to first solve for charge of the spherical conductor and second, find the radius( Easy to solve once we know charge)

Homework Equations


V=kq/r
V=E*integral dr
many others

The Attempt at a Solution


I've been trying to find a way to cancel out radius and solve for q but I can't seem to do it. Someone please help I need to turn this in by tomorrow morning thanks.

EDIT never mind
 
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I just found the answer. We use this equation:V = kq/r where V is the total potential, k is a constant (k=8.99x109 N*m2/C2), q is the charge, and r is the radius of the sphere.Solving for q, we get:q = V*r/k For our given values, we have V=580 kV, r=unknown, and k=8.99x109 N*m2/C2. Plugging in these values yields:q = 580 kV*r/8.99x109 N*m2/C2 Now that we know the charge, we can calculate the radius by rearranging our original equation:r = kq/V Plugging in our known values, we get: r = 8.99x109 N*m2/C2 * 580 kV/8.99x109 N*m2/C2 Simplifying gives us:r = 580 kV Thus, the charge of the spherical conductor is 580 kV and the radius is also 580 kV.
 
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