How Do You Calculate Enantiomer Percentages from Enantiomeric Excess?

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A natural product with an enantiomeric excess (ee) of 84% indicates a significant imbalance between its enantiomers. The calculation for determining the percentages of each enantiomer involves using the formula for enantiomeric excess. In this case, the major enantiomer constitutes 92% of the mixture, while the minor enantiomer accounts for 8%. This reflects the fundamental principle that enantiomeric excess quantifies the difference in concentration between two enantiomers in a chiral mixture.
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If a natural product was isolated and was found to have an enantiomeric excess (ee) of 84% what would be the percentages of each enatiomer in the mixture?
 
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Well, do you know the equation (or definition) of enantiomeric excess?
 
uorganic said:
If a natural product was isolated and was found to have an enantiomeric excess (ee) of 84% what would be the percentages of each enatiomer in the mixture?

think about it...

how many possible enantiomers are there. hint: the number of possible enantiomers is the same for any compound.

so...let's say that the enantiomers were 50:50 in a mixture. then, the excess would be 0. if it were a 40:60 mixture, then one of the enantiomers would be in 10% excess. notice that (60 - (100 - 60) ) / 2 = 10

see the pattern here?
 
Enantiomeric excess (ee) of 84%

Then major isomer % = (100+84)/2 = 92 %

%minor isomer = 100-92 = 8%

regards
kandasani
 

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