How Do You Calculate Tensions in a Dual-Block and Rope System?

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To calculate the tensions in a dual-block and rope system, the problem involves two 1.0 kg blocks connected by ropes, with an additional rope hanging beneath the lower block. The entire system is accelerated upward at 3 m/s², requiring the application of Newton's second law. The net force equation is Fnet = 2.5 * -9.8 + F, and tensions are calculated using T = g(mass of all things under it). Initial attempts at calculating the tensions yielded incorrect results, indicating a need for clarification or a proper diagram to visualize the forces involved. Accurate tension calculations depend on correctly accounting for all masses and the applied force in the system.
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Homework Statement



The figure shows two 1.0 kg blocks connected by a rope. A second rope hangs beneath the lower block. Both ropes have a mass of 250 g. The entire assembly is accelerated upward at 3m/sec^2 by force F.

What are the following tensions:

1. The tension of the top of rope 1.
2. The tention of the bottem of rope 1.
3. The tension of the top of rope 2.

Includes the following diagram
[A]
|1

|2


Homework Equations


Fnet = 2.5*-9.8+F
T=g(mass of all things under it)

The Attempt at a Solution



Tsub1 = (.25+.25+1)g
Tsub2 = .25g

But these answers are wrong...
 
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Can't make sense of it with no diagram.
 

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