How Do You Calculate the Force Constant of a Copper Wire Using Young's Modulus?

  • Thread starter Thread starter dazza67
  • Start date Start date
  • Tags Tags
    Lost Modulus
AI Thread Summary
To calculate the force constant of a copper wire using Young's modulus, the formula k = Y * A / L can be applied, where k is the force constant, Y is Young's modulus, A is the cross-sectional area, and L is the length of the wire. The user struggled with understanding how to apply this formula and converting units into base units for clarity. They found that working in scientific notation helped clarify their calculations. After receiving guidance, they expressed gratitude and indicated they were now on the right track. This discussion emphasizes the importance of unit conversion and dimensional analysis in solving physics problems.
dazza67
Messages
2
Reaction score
0

Homework Statement



Help I have spent a couple of days on this one and I am lost...

What would the force constant be for a 75.0 cm length of 16-gauge (dia=1.291mm) copper wire? Y copper=11x10^10 Pa
The answer being in Nm.
The problem is I don’t even know where or how to approach this problem as when I have looked at hookes law and Young’s I fail to see how to fit this problem into the equations. I will accept lack of understanding, fatigue, or just plain stupidity on my behalf. If someone could spare the time to step me through it, i don't need this solved, just the steps so I can solve it myself. I would be grateful thanks



Homework Equations





The Attempt at a Solution


Basically 8 pages of incomprehensible gibberish
 
Physics news on Phys.org
I just answered that same question about steel. The units of Y are N/m^2. The force constant k is N/m. Let the cross sectional area be A and the length L. A REALLY good guess would be k=Y*A/L. Wouldn't it? Think dimensional analysis. Confirm it by looking it up or applying physical intuition.
 
Sloved--- yeh

Dick thanks for your help. The big issue I found is to change every thing into base units and work in scientific notation, a big part of my problem, how ever your gental push in the right direction has me now on track Big thanks
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top