How do you calculate the line integral of f(x,y,z) from (1,2,3) to (0,-1,1)?

dwn
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Homework Statement



Find the line integral of f(x,y,z) = x+y+z over the straight-line segment from (1,2,3) to (0,-1,1).

Homework Equations



∫ f(x,y,z)ds = ∫ f(g(t), h(t), k(t)) |v(t)| dt

The Attempt at a Solution



I arrived at the correct solution, but I'd like some clarity on the result.

The final answer to this is 3√(14) or -3√(14) depending on which point you choose as your parametric equation.
x = -t
y = -3t-1
z = -2t+1
From using the point (0,-1,1) and (-1,-3,-2) as my direction vector.

What I would like to understand is the meaning of the positive and negative result. Does it matter?
It just seems to me that my result should have been positive since I am moving from a lower position to a higher position, no?BTW, QUICK SHOUTOUT TO PF --- THE NEW SITE IS AMAZING! GREAT JOB ON THE NEW LAYOUT.
 
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dwn said:

Homework Statement



Find the line integral of f(x,y,z) = x+y+z over the straight-line segment from (1,2,3) to (0,-1,1).

Homework Equations



∫ f(x,y,z)ds = ∫ f(g(t), h(t), k(t)) |v(t)| dt

The Attempt at a Solution



I arrived at the correct solution, but I'd like some clarity on the result.
Which is the correct solution? You show 2 different values below.
The final answer to this is 3√(14) or -3√(14) depending on which point you choose as your parametric equation.
x = -t
y = -3t-1
z = -2t+1
From using the point (0,-1,1) and (-1,-3,-2) as my direction vector.

How did you arrive at this parameterization for the line segment specified? For example, if t = 0, does your parameterization return the (x,y,z) of the first point on the line segment?

What I would like to understand is the meaning of the positive and negative result. Does it matter?

Yes, it matters. Some line integrals are path independent. Is this one?

It just seems to me that my result should have been positive since I am moving from a lower position to a higher position, no?

How did you arrive at this conclusion? The OP states that the line integral is to be taken over the line segment from (1,2,3) to (0,-1,1), not the other way around.
 
Correct Answer: 3√(14) but I got the negative term because I used the wrong point as my starting position.Why does direction of the integral matter though? Because the value of the integral will remain the same. I see that they are asking us to go from a specified point and not the other, but is it really necessary?
 
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Is ##\int_{a}^{b} f(x) dx = \int_{b}^{a} f(x) dx ## ?
 
No it is not.

I actually have a question about a and b though. How do we determine the interval? I still don't quite understand that.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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