How Do You Calculate the Mass of Silver Using Constant Pressure Calorimetry?

AI Thread Summary
To calculate the mass of silver using constant pressure calorimetry, the heat lost by the silver equals the heat gained by the water. The specific heat of silver is 0.235 J/g°C, and for water, it is 4.184 J/g°C. The equation q = m * s * ΔT is used, where q represents heat, m is mass, s is specific heat, and ΔT is the change in temperature. By setting the heat lost by the silver equal to the heat gained by the water, the mass of the silver can be determined. This approach simplifies the problem to a single equation that can be solved for the mass of silver.
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The specific heat of silver is 0.235J/gC and the specific heat of water is 4.184J/gC. A piece of silver at 94.31C was dropped into a constant pressure calorimeter containing 148g of water at 24.08C. The final temperature of the water and silver was 25.39C. Assuming that the calorimeter itself absorbs a negligible amount of heat, whatw as the mass of the silver?

This is the problem at hand, and I am on the tail end of a large study period and have finished a worksheet minus this particular problem. I would appreciate the help. Thanks.
I just don't not understand what equations to use/ how to modifythem
q=m.s.(change in temp). q=C(change in temp)?
 
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heat lost by silver = heat gained by water

heat = mass x specific heat x change in temperature

It leads to one simple equation that you have to solve for silver mass.
 
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