How Do You Calculate the Outcome of an Elastic Collision on Frictionless Slopes?

  • Thread starter Thread starter stacerho
  • Start date Start date
  • Tags Tags
    Homework
AI Thread Summary
The problem involves a 350 kg mass released from a height of 3.2 m on a frictionless slope, colliding elastically with a stationary 468 kg mass. The key concepts include conservation of momentum and conservation of kinetic energy during the elastic collision. After the collision, the kinetic energy of the 468 kg mass is converted into potential energy as it slides up a similar slope. To solve for the speed of the 468 kg mass after the collision and its maximum height, one must apply these conservation principles. Understanding these mechanics is crucial for solving similar physics problems effectively.
stacerho
Messages
6
Reaction score
0
here is my problem:


The surfaces are frictionless. The tracks are 60degrees from horizontal. A 350 kg mass is released from rest on a track at a height 3.2 m above a horizontal surface at the foot of the slope. It collides elastically with a 468 kg mass initially at rest on the horizontal surface. The mass 468 kg slides up a similar track. The acceleration of gravity is 9.8m/s^2.

Part 1) What is the speed of the block 468 kg immediately after the collision? Answer in units of m/s.

Part 2) To what maximum height h2 above the horizontal surface will the mass 468 kg slide? Answer in units of m.
 
Physics news on Phys.org
What have you attempted thus far?
 
Nothing, I'm completely stumped, I don't even know where to begin. this class has just driven me crazy. I'm having a baby in a few weeks and just cannot figure this stuff out it's completely warn me out.
 
stacerho said:
Nothing, I'm completely stumped, I don't even know where to begin.

What textbook are you using for this class. What does it say about what happens in elastic collisions? Is any particular quantity conserved?

Congratulations on the upcoming baby, BTW!
 
stacerho said:
here is my problem:


The surfaces are frictionless. The tracks are 60degrees from horizontal. A 350 kg mass is released from rest on a track at a height 3.2 m above a horizontal surface at the foot of the slope. It collides elastically with a 468 kg mass initially at rest on the horizontal surface. The mass 468 kg slides up a similar track. The acceleration of gravity is 9.8m/s^2.

Part 1) What is the speed of the block 468 kg immediately after the collision? Answer in units of m/s.

Part 2) To what maximum height h2 above the horizontal surface will the mass 468 kg slide? Answer in units of m.

You just draw force arrows (composants) for the initial configuration (all forces). In the elastic collision no kinetic energy is transformed to heat.
Potential energy ( initial) Becomes kinetic energy when you release the 350kg, and in the collision the two bodies "share" the energy so that linear momentum is conserved. Then the kinetic energy of the 468kg is transformed into potential energy (when it slides up the slope).

This is the procedure for ALL basic mechanics problems. Find all forces, draw composants, find the acceleration, energy (if elestic and no friction, that means no kinetic energy is transformed into heat) and momentum conservations.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top