How Do You Calculate the Required Thickness of Aluminum for a Box?

AI Thread Summary
To calculate the required thickness of aluminum for a box designed to hold a 350-gram amplifier, the user seeks a specific formula. They mention that 1.6mm or 16 gauge aluminum is typically suitable but want to validate this scientifically. The discussion references the bending moment (M) and stress (σ) equations, indicating a need for structural analysis. However, the user emphasizes the lack of accessible formulas online for this calculation. The conversation centers on finding the appropriate mathematical approach to determine material thickness.
SP_RED
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Homework Statement


i am trying to work out the required material thickness for a given box.
the material i am using is aluminium.
i only require the formula - can't find a suitable one on web


Homework Equations





The Attempt at a Solution



M = I
σ y

M = bd M = bd2
σ 12/2 σ 6
 
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SP_RED said:

Homework Statement


i am trying to work out the required material thickness for a given box.
the material i am using is aluminium.
i only require the formula - can't find a suitable one on web


Homework Equations





The Attempt at a Solution



M = I
σ y

M = bd M = bd2
σ 12/2 σ 6

Welcome to the PF. Required thickness for what?
 
SP_RED said:

Homework Statement


i am trying to work out the required material thickness (gauge) for a box i am making which is designed to hold an amplifier weighing 350grams.

the material i am using for the boxes is aluminium.

i know that 1.6mm or 16 gauge is more the suitable but i am just trying to prove it through the appliance of science/maths.

i only require the formula - can't find a suitable one on web


Homework Equations





The Attempt at a Solution



M = I
σ y

M = bd M = bd2
σ 12/2 σ 6
 
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