How Do You Calculate the Time and Speed of a Falling Object?

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To calculate the time it takes for a stone to fall from a height of 51.2 meters, use the formula t = √(2h/g), resulting in approximately 3.2 seconds. The speed just before it strikes the ground can be found using v = gt, yielding about 31.36 m/s. To determine the distance fallen during the last second, calculate the total distance fallen in 3.2 seconds and subtract the distance fallen in 2.2 seconds, resulting in approximately 4.9 meters. Reviewing the Basic Equations of 1-D Kinematics is essential for accurate calculations. Proper application of these formulas will clarify the process and help resolve any confusion.
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Hey guys,
Just wondering if you could please help me decode this question as well as put a little explanation as to how you got that answer. I am really struggling to get the correct calculations

(Take g = 9.8 m.s -2)

A stone is dropped from a height of 51.2 metres from the ground.
(a) How long does it take to reach the ground?
(b) What speed just before it strikes the ground?
(c) How far does it fall during the last second of it's fall?


Thanks!
 
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