Logarythmic
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I have two parametric equations for the speed of a particle in a plane:
\dot{x}(t) = A \left( 1 - cos{\Omega t} \right)
\dot{y}(t) = A sin{\Omega t}
The period is equal to \Omega. How do I find the wavelength of the motion?
The wavelength is just \lambda = \Omega v, where v = \sqrt{\dot{x}^2 + \dot{y}^2} is the speed, right? But then the wavelength is not time invariant. Could my answer
\lambda = \Omega A \left( 2 - 2cos{\Omega t} \right)^{1/2}
really be correct?
\dot{x}(t) = A \left( 1 - cos{\Omega t} \right)
\dot{y}(t) = A sin{\Omega t}
The period is equal to \Omega. How do I find the wavelength of the motion?
The wavelength is just \lambda = \Omega v, where v = \sqrt{\dot{x}^2 + \dot{y}^2} is the speed, right? But then the wavelength is not time invariant. Could my answer
\lambda = \Omega A \left( 2 - 2cos{\Omega t} \right)^{1/2}
really be correct?