How Do You Calculate Thermodynamic Properties in Different Expansion Processes?

AI Thread Summary
The discussion focuses on calculating thermodynamic properties for two different expansion processes involving helium and an ideal gas. For the reversible adiabatic expansion, participants suggest using the ideal gas law and the relationship between pressure and volume to derive work, internal energy, and enthalpy changes. In the case of the reversible isobaric expansion, it is noted that heat can be calculated directly from the change in internal energy and the work done at constant pressure. The importance of understanding the specific heat capacities (Cv and Cp) for these calculations is emphasized. Overall, the thread seeks clarification on the derivation of these equations and the application of thermodynamic principles.
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Hi all , I have 2 questions, I don't know how to derive the equations, please help.
Thank you.
1)A reversible adiabatic expansion of 2.5 moles or He from a volume 9L at 300K to a final volume of 28L.
Find work(W), heat(Q), internal energy(U) and enthalpy change(H) and final temperature. (He is a monatomic ideal gas)

2)A reversible isobaric expansion of an ideal gas from P1,V1,T1 to P1,V2,T2, assume Cv = 5/2nR
Find W, change in internal energy, Heat and enthalpy.

I know for #1 heat = 0, therefore delta U = W = integral P*dV, but I don't know since we don't know pressure , I don't know how to continue.

For #2, it is constant pressure, therefore W= -P*delta V
delta U = Q - (p*delta V)
Q = delta U + (p*delta V) = enthalpy
Am I right ? it looks so weird, I need some help thanks !
 
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1. Adiabatic work done, W = \int PdV. But PV^{\gamma} = const, ~C gives :

W = C~\int \frac{dV}{V^{\gamma}}

Integrate that out, find P using the Ideal Gas Law, use the value of \gamma for an ideal monoatomic gas, and hence find the value of the adiabatic constant C. Plug in values of C, Vf and Vi to find the work done.

2. For an isobaric process, Q is easily found. Recall what Cp is ?
 
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