How Do You Calculate Turntable Rotation and Acceleration?

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The discussion revolves around calculating the turntable's rotation and acceleration after it is turned off. The turntable has an initial angular speed of 3.5 rad/s and stops in 1.6 seconds, with a radius of 15 cm. The first part of the problem involves determining the radians turned after being turned off, while the second part focuses on finding the linear acceleration of a point on the rim after 1 second. Participants suggest using kinematic equations by converting the problem into linear motion terms to simplify calculations. Understanding angular acceleration is crucial for solving both parts of the problem effectively.
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I know this is not typical and you aren't suppose to solve the problem for the person just give hints, however my teacher has not taught this and expects us to know it. For whatever I cannot grasp how to do this any help would be great thank you!

1. Homework Statement

The turntable of a record player has an angular speed of 3.5 rad/s at the instant it is turned off. The turntable stops 1.6s after being turned off. The radius of the turntable is 15cm. (a) If the angular acceleration is constant, through how many radians does the turntable turn after being turned off? (b) What is the magnitude of the linear acceleration of a point on the rim of the turntable 1.0s after it is turned off? (Hint: The linear acceleration has both a radial and a tangential component).

Homework Equations


We have not been given any equations yet, we were just told to use the position function and ones used in projectile motion problems.

The Attempt at a Solution


for a I got 4.375 I took 3.5(1.6/2). Is this right? I don't really have any reasonings for why I did it. I don't understand how to do b. If you could send me down the right path with that one it would be greatly appreciated.
 
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The equations for rotational motion have a one-to-one correspondence with those for kinematics, just the variable names change.

Convert the "story" to linear motion terms so that you can think about it on familiar grounds:

An object has a linear speed of 3.5 m/s at the instant it is released on a flat surface. It coasts to a stop 1.6 second after being released. If the acceleration is constant, what is the distance it traveled after release?
 
gneill said:
The equations for rotational motion have a one-to-one correspondence with those for kinematics, just the variable names change.

Convert the "story" to linear motion terms so that you can think about it on familiar grounds:

An object has a linear speed of 3.5 m/s at the instant it is released on a flat surface. It coasts to a stop 1.6 second after being released. If the acceleration is constant, what is the distance it traveled after release?
Thank you very much that helped me with a but how do I even approach b this is where I was really thrown through the loop. I tried to find the velocity at 1 s with no success.
 
thegoosegirl42 said:
Thank you very much that helped me with a but how do I even approach b this is where I was really thrown through the loop. I tried to find the velocity at 1 s with no success.
Did you calculate the angular acceleration while answering part (a)?
 
Would that be the acceleration divided by the radius?
 
thegoosegirl42 said:
Would that be the acceleration divided by the radius?
Well, yes, it would be equal to the tangential acceleration divided by the radius. I thought you might have determined it from the initial and final angular velocities and the stopping time. It'll come in handy for writing the equation of motion for the turntable w.r.t. time.
 
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