How Do You Calculate Vrms for a Neutron in a Reactor Core?

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To calculate the root mean square velocity (Vrms) of a neutron in a reactor core at 400K, the correct mass to use is 1.0 x 10^-3 kg/mole, which represents the molar mass of neutrons. A mole of neutrons corresponds to Avogadro's number, approximately 6.022 x 10^23 neutrons. The mass per neutron should be derived from this molar mass divided by Avogadro's number, ensuring consistent units in calculations. The discussion highlights the importance of understanding the distinction between mass in kg and molar mass in kg/mole for accurate computations. Clarifying these concepts is essential for solving similar problems involving particles like electrons and protons.
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Homework Statement



The equation for the "average" velocity of a gas molecule
in a closed container is:

Vrms = ( 3 x k x T / m )^ 1/2 where

k = 1.38 x 10 ^ 23 Joules/K

T is temp in Kelvin

m = mass per ion in kg = Atomic Mass M / Avagadro's Number Na

so for N2, I can calculate m = (28 grams/mole) / 6.02 x 10^23 ions/mole

and get m = 4.65 x 10^-23 grams/ ION , which I change to 4.65 x 10^-26 kg/ION

Homework Equations



Vrms = ( 3kT/m)^1/2

I read the 28 grams/mole from the Atomic Table. ( 14 + 14 for N2 ).

And I realize that m must be in kg because of the units of k.


The Attempt at a Solution



( trying to edit out some errors here )

Now, I'm given the problem of calculating Vrms of a neutron
in the core of a reactor at 400K. I looked up the mass of
the neutron on-line and got 1.675 x 10^-27 kg .. OK, fine!

But I can't use that for Atomic Mass M. Instead the proper M = 1.0 x 10^-3 kg/mole

And the lab book uses the formual Vrms = ( 3k Na T )/ M )^1/2 where

m = M / Na .. atomic weight / Avagadro's number

This must be an elementary question, but why is M = 10^-3 kg/mole
for the neutron ? .. as used in the book ? What is a mole
of neutrons ??
 
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johns123 said:
Now, I'm given the problem of calculating Vrms of a neutron
in the core of a reactor at 400K. I looked up the mass of
the neutron on-line and got 1.675 x 10^-27 kg .. OK, fine!

But I can't use that for m. Instead the proper m = 1.0 x 10^-3 kg/mole

This must be an elementary question, but why is m = 10^-3 kg/mole
for the neutron ? .. as used in the book ? What is a mole
of neutrons ??

A mole of anything is Avogadro's number ##N_\mathrm{A} = 6.022141 \times 10^{23}## units of that thing. Therefore, 1 mole of neutrons is ##6.022141 \times 10^{23}## neutrons. I'll let you figure out the mass of that :smile:
 
Reading more carefully, I don't understand why you need to know the molar mass of neutrons. Your units are not consistent, as in
so for N2, I can calculate m = (28 grams/mole) / 6.02 x 10^23 ions/mole

and get m = 4.65 x 10^-23 grams/ mole , which I change to 4.65 x 10^-26 kg/mole
m should be in units of mass, kg, not in kg/mol.
 
I just reedited the problem above. Hope the errors are gone!

My mistake. I meant m = 4.65 x 10^-23 grams/ion which I have to change to kg/ion. Also, I'm reading online at Yahoo that the problem should have specified a gas like Li where I could calculate Kg/mole of Li; go to kg/ion of Li, and then realize that Li has a few neutrons per atom .. and THAT would give kg/mole of neutrons which I could reduce to m = M/Na for that number of neutrons in 1 mole of Li.. That is really chasing me in circles trying to completely understand it.. And the problems coming after are the same, but for electrons and protons. I think I better get a grasp on the neutrons first. Thanks
 
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