- #31
romiomustdie
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i didnt get the equation ... how did you get the above equation ?
How Do You Derive the Distance Traveled by a Projectile in a Viscous Liquid?
- Thread starter romiomustdie
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Homework Help Overview
The discussion revolves around deriving the distance traveled by a projectile in a viscous liquid, where the projectile is fired horizontally with an initial velocity \( V_0 \). The problem involves understanding the effects of a retarding force that is proportional to the square of the velocity, leading to a specific acceleration equation \( a = -kV^2 \). Participants are tasked with deriving an expression for the distance \( D \) traveled in the liquid and the time required to reduce the velocity to \( V_0/2 \), while neglecting any vertical motion.
Discussion Character
- Mixed
Approaches and Questions Raised
- Participants discuss various attempts to solve the problem, including the use of differential equations and integration techniques. Some express confusion about the correct application of formulas and the integration process needed to find distance from velocity.
Discussion Status
The discussion is ongoing, with some participants providing guidance on the use of differential equations and integration. There is a recognition of the need to correctly derive the velocity equation before proceeding to find the distance. Multiple interpretations and approaches are being explored, but no consensus has been reached on a complete solution.
Contextual Notes
Participants mention constraints such as impending exams and varying levels of familiarity with calculus and differential equations, which may affect their ability to engage with the problem effectively.
- #32
romiomustdie
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ok got it
- #33
romiomustdie
- 29
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but how will i get a numerical value like 0.693 in numerator by splving this . i am not getting what to do , ?
- #34
romiomustdie
- 29
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but how will i get a numerical value like 0.693 in numerator by solving this by integration to obtain S .
i am not getting what to do , ? Totally puzzed , please do the rest please
i am not getting what to do , ? Totally puzzed , please do the rest please
- #35
- 23,718
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Start by using the velocity equation to find the time at which the velocity is half its initial value.
Chet
Chet
- #36
romiomustdie
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- #37
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Yes. Now integrate to get the distance. Let's see your work.romiomustdie said:
Chet
- #38
romiomustdie
- 29
- 0
Failure failure failure
Unable to find out the distance please show
Unable to find out the distance please show
- #39
romiomustdie
- 29
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Log and all coming
- #40
romiomustdie
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Please show
- #41
vela
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We don't do the problems for you. You need to figure them out.
- #42
romiomustdie
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Give some hint then
- #43
romiomustdie
- 29
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I am struggling with this problem for a long time. One question I solved but unable to find Distance
- #44
vela
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Supposedly you got the velocity, and then all you've written about getting the position is "failure failure failure."
Here's a hint: Try again.
The relationship between acceleration and velocity is analogous to that between velocity and position. If you understood how to get v from a, it's exactly the same mathematical process to get x from v.
Here's a hint: Try again.
The relationship between acceleration and velocity is analogous to that between velocity and position. If you understood how to get v from a, it's exactly the same mathematical process to get x from v.
- #45
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dx=Vdtromiomustdie said:
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