How Do You Derive the Distance Traveled by a Projectile in a Viscous Liquid?

[romiomustdie]

i didnt get the equation ... how did you get the above equation ?

 

[romiomustdie]

ok got it

 

[romiomustdie]

but how will i get a numerical value like 0.693 in numerator by splving this . i am not getting what to do , ?

 

[romiomustdie]

but how will i get a numerical value like 0.693 in numerator by solving this by integration to obtain S .

i am not getting what to do , ? Totally puzzed , please do the rest please

 

[Chestermiller]

Start by using the velocity equation to find the time at which the velocity is half its initial value.

Chet

 

[romiomustdie]

 

[Chestermiller]

View attachment 89943

Yes. Now integrate to get the distance. Let's see your work.

Chet

 

[romiomustdie]

Failure failure failure

Unable to find out the distance please show

 

[romiomustdie]

Log and all coming

 

[romiomustdie]

Please show

 

[vela]

We don't do the problems for you. You need to figure them out.

 

[romiomustdie]

Give some hint then

 

[romiomustdie]

I am struggling with this problem for a long time. One question I solved but unable to find Distance

 

[vela]

Supposedly you got the velocity, and then all you've written about getting the position is "failure failure failure."

Here's a hint: Try again.

The relationship between acceleration and velocity is analogous to that between velocity and position. If you understood how to get v from a, it's exactly the same mathematical process to get x from v.

 

[Chestermiller]

Please show

dx=Vdt