How Do You Determine the Interval of Convergence for a Series?

knv
Messages
17
Reaction score
0
1. Find the radius and the interval of convergence for the series:

Ʃ n=2 --> inf : [(-1)nxn]/ [4nln(n)]





2.To find the radius, we use the alternating series test. **an+1/an




3. From the alternating series test I find that the limit as n --> inf = 4. So our radius is 4. Although I do not know how to get the intervals from the radius. Can anyone help me?

Would we just plug in ±4 for x and solve for convergence or divergence?
 
Last edited by a moderator:
Physics news on Phys.org
knv said:
1. Find the radius and the interval of convergence for the series:

Ʃ n=2 --> inf : [(-1)nxn]/ [4nln(n)]





2.To find the radius, we use the alternating series test. **an+1/an
You mean the ratio test.
3. From the alternating series test I find that the limit as n --> inf = 4. So our radius is 4. Although I do not know how to get the intervals from the radius. Can anyone help me?

Would we just plug in ±4 for x and solve for convergence or divergence?

Yes. You know you have convergence for ##-4 < x < 4##. So just check to see which, if any, of the end points to include.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Replies
4
Views
1K
Replies
5
Views
1K
Replies
11
Views
3K
Replies
3
Views
1K
Replies
24
Views
3K
Replies
5
Views
2K
Replies
2
Views
880
Back
Top