How do you find acceleration when you are only given netwons?

  • Thread starter Thread starter AznBoi
  • Start date Start date
  • Tags Tags
    Acceleration
AI Thread Summary
To find acceleration when given forces in newtons, first calculate the net force by subtracting the downward weight from the upward force, resulting in -460 N. Next, determine the mass by dividing the weight (480 N) by gravitational acceleration (approximately 9.81 m/s²). Finally, divide the net force (-460 N) by the mass to find the acceleration. Correct terminology is crucial for clarity, as mass is derived from weight using the formula m = W/g. Understanding these steps ensures accurate calculations in physics problems involving forces.
AznBoi
Messages
470
Reaction score
0
Okay, there is 20 N of force upward and there is 480N of weight pulling down, how do I find the acceleration??
 
Physics news on Phys.org
AznBoi said:
Okay, there is 20 N of force upward and there is 480N of weight pulling down, how do I find the acceleration??

Net force is then 20N - 480N = -460N.

Divide by the mass (F = ma).
 
nvm I got it, you just divide N by gravity (dumb me) to get the mass then dvide the N by mass to get acceleration! Thanks anyways! :smile:
 
AznBoi said:
nvm I got it, you just divide N by gravity (dumb me) to get the mass then dvide the N by mass to get acceleration! Thanks anyways! :smile:
Just so you don't confuse people, I think you get the point but your terminology is wrong. You divide the weight by gravitational acceleration to get the mass (W = mg so m = W/g). You then divide the net force by the mass to get the mass' acceleration (F/m = a).

AM
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top