How do you find out the exponent if you can't use logs?

  • Thread starter Thread starter priceofcarrot
  • Start date Start date
  • Tags Tags
    Exponent
Click For Summary

Homework Help Overview

The discussion revolves around understanding how to determine exponents without using logarithms, specifically in the context of equations involving powers of 2 and 3. Participants are examining examples such as \(2^{(2x+1)} = \frac{1}{32}\) and \(3^{(x-1)} = 27\), questioning the reasoning behind identifying the exponents.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants express confusion about how to ascertain the exponent values without logarithmic methods. There are inquiries about whether the process involves trial and error or if there are simpler formulas to determine the relationship between numbers and their exponents. Some suggest that memorizing powers of small numbers could be beneficial.

Discussion Status

The conversation is ongoing, with participants sharing their thoughts on memorization of powers and the potential for using multiplication sequences to derive exponent values. There is no clear consensus, but various perspectives on the approach to understanding exponents are being explored.

Contextual Notes

Some participants mention the importance of knowing specific powers of numbers, while others question the necessity of memorization versus understanding the underlying concepts. The discussion reflects a mix of approaches and assumptions regarding the nature of exponentiation.

priceofcarrot
Messages
32
Reaction score
0


There isn't a problem here, it's an example they gave, but I don't get how you can get the answer without using logs.

2^(2x+1) = 1/32
2^(2x+1) = 2^(-5)

How do they know that it's -5?


Same thing for:

3^(x-1) = 27
3^(x-1) = 3^3



Is it just trial and error? I've tried a bunch of different methods but none have worked.
 
Physics news on Phys.org
priceofcarrot said:
There isn't a problem here, it's an example they gave, but I don't get how you can get the answer without using logs.

2^(2x+1) = 1/32
2^(2x+1) = 2^(-5)

How do they know that it's -5?
Because 32 = 25, that's how. So 1/32 = 1/(25) = 2-5.
priceofcarrot said:
Same thing for:

3^(x-1) = 27
3^(x-1) = 3^3
You know that 32 = 9, right, so 33 = 27. That's all it is.
priceofcarrot said:
Is it just trial and error? I've tried a bunch of different methods but none have worked.
No, it's not trial and error. It's useful to know a few powers of small numbers.

2, 4, 8, 16, 32, 64, 128, 256, 512, 1024 correspond to exponents on 2 of 1, 2, 3, ..., 10

3, 9, 27, 81, 243 correspond to exponents on 3 of 1, 2, 3, 4, and 5

and so on.
 
Is there any simple formula I can use to find that 32 = 2^5? Or similar things, or is it just having an idea which numbers as the exponent would produce which numbers?

Can I just knowing 32 = 2^x find out what x is with a formula?
 
priceofcarrot said:
Is there any simple formula I can use to find that 32 = 2^5? Or similar things, or is it just having an idea which numbers as the exponent would produce which numbers?

Can I just knowing 32 = 2^x find out what x is with a formula?
Just memorize some of the powers, as Mark44 said. It really isn't much different than memorizing addition and multiplication facts (except that the numbers are bigger, of course).
 
Or you might notice that 32 = 2 * 16 = 2 * 2 * 8 = 2 * 2 * 2 * 4 = 2 * 2 * 2 * 2 * 2 = 25.

Do you know how to factor a number into its prime factors?
 
priceofcarrot said:
Is there any simple formula I can use to find that 32 = 2^5? Or similar things, or is it just having an idea which numbers as the exponent would produce which numbers?

Can I just knowing 32 = 2^x find out what x is with a formula?

Sure. You start out with 1, and then multiply it by 2 to get 2. Then you multiply the 2 by 2 to get 4. Then you multiply the 4 by 2 to get eight. Then you multiply the 8 by 2 to get 16. Then you multiply the 16 by 2 to get 32. How many multiplications did you do all together to get 32?
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
Replies
2
Views
2K
Replies
10
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
13
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
18
Views
4K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
8
Views
2K