How do you find the adjoint of a 3x3 matrix? can u explain example?

mr_coffee
Messages
1,613
Reaction score
1
Hello everyone, I think i don't understand the inverses because i don't understand how u find the adjoint of a nxn matrix. The book has this example and i have no idea how they got from A to A adj, makes no sense to me!

Here is the picture:
http://img89.imageshack.us/img89/3010/lastscan0oo.jpg
if that link is slow try:L
http://show.imagehosting.us/show/806170/0/nouser_806/T0_-1_806170.jpg
thanks! :biggrin:
 
Last edited by a moderator:
Physics news on Phys.org
mr_coffee said:
Hello everyone, I think i don't understand the inverses because i don't understand how u find the adjoint of a nxn matrix. The book has this example and i have no idea how they got from A to A adj, makes no sense to me!
Here is the picture:
http://img89.imageshack.us/img89/3010/lastscan0oo.jpg
if that link is slow try:L
http://show.imagehosting.us/show/806170/0/nouser_806/T0_-1_806170.jpg
thanks! :biggrin:

To find the adjoint of a A:

<br /> adj(A)_{ij} = (-1)^{i+j} det[A(j|i)]<br />

That means that the entry in the row i and column j of adj(A) is obtained by deleting the column j and the row i of A and then taking the determinant of that and multipliying by (-1)^{i+j}

For instance if u have a 3x3 matrix:
http://en.wikipedia.org/math/e36e0138b126ebbcf8fe80cd4f58f3aa.png

this is the adjoint:
http://en.wikipedia.org/math/a3c81ad8680add569a7377cda2529147.png
 
Last edited by a moderator:
Ahh thank u so much!
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top