How Do You Find the Inverse Laplace Transform of (1/6)/((s+2)^2)?

Khamul
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Hello everyone, I'm currently enrolled in Control Theory at my University, and part of the coursework requires differential equations; which wouldn't be a problem, if not for the fact it's been 2 years since I've taken D.E. Anyway, over the course of the problem I ran into this little function, and it's giving me a rough time..F(s) = (1/6) / ((s+2)^2)

I'm attempting to take the inverse Laplace, but I'm not finding any explicit transform pairs that fit this function. I'll be honest, I remember that you're able to shift the function, but I have no recollection of how to do so. Would anyone be so kind as to help me out with this little bugger? I have the rest of the problem complete except for this stickler. Thank you in advance! :)
 
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Look into properties of the Laplace transform that relate what you have to known transforms in the table. They're likely listed in the table as well.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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