How Do You Integrate a Wave Function to Find Electron Probability?

AI Thread Summary
To find the electron probability using the wave function ψ2(x) = sqrt(2/L) sin(2πx/L), the probability density must first be computed as |ψ2(x)|² = (2/L) sin²(2πx/L). The integration should then be performed between the limits of x = 0 and x = L/6. The half-angle identity for sine, sin²(x) = 1/2(1 - cos(2x)), can simplify the integration process. This approach allows for the calculation of the probability of locating the electron within the specified range.
bemigh
Messages
29
Reaction score
0
Hey. I am pretty confident i have solve this problem. I just solve the integral of the given wave function, with the given limits... However, I am having a difficult time integrating it. The sqrt(2/L) can be brought outside of the integral, but what can i with the sin function?


The wave function of an electron is
ψ2(x) = sqrt(2/L) sin(2πx/L)
Calculate the probability of finding the electron between x = 0 and x = L/6.

Cheers
 
Physics news on Phys.org
So what is the problem...?Compute the probability density first,and then integrate the result between the 2 limits specified in the problem...

Daniel.
 
One-dimensional infinite square well I assume. What's wrong?

\psi_2 (x) = \sqrt{\frac{2}{L}} \sin{\frac{2\pi x}{L}} \Longrightarrow | \psi_2(x) |^2 = \frac{2}{L}\sin^2{\frac{2\pi x}{L}}

integrate from 0 to \frac{L}{6}... If you don't remember the half-angle identity, here it is:

\sin^2{x} = \frac{1}{2}(1-\cos{2x})
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top