How Do You Integrate Absolute Values with Complex Exponentials?

Xkaliber
Messages
59
Reaction score
0

Homework Statement



<br /> \int_{-3}^{3}|t|e^{-jwt}dt<br />


The Attempt at a Solution



I am not sure if I need to break this into two regions due to the abs value...
 
Physics news on Phys.org
Yes, that is one approach:

\int_{-3}^3 |t| e^{-j \omega t} \, dt = \int_{0}^3 t e^{-j \omega t} \, dt - \int_{-3}^0 t e^{-j \omega t} \, dt
and then you can solve both integrals with a trick (write the integrand as a derivative w.r.t. omega, for example).

Alternatively, you can use Euler's identity to write the integral as

\int_{-3}^3 |t| \cos(\omega t) \, dt + j \int_{-3}^3 |t| \sin(\omega t) \, dt
and use (anti)-symmetries to reduce the problem before taking care of the absolute value.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top