How Do You Integrate sec^6(t)?

afcwestwarrior
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Homework Statement



∫sec^6 t

Homework Equations


sec^2 (x)=1+tan^2 (x)


The Attempt at a Solution


∫ (sec^2 (t))^2 * (Sec^2 (t))^2

∫(1+tan^2 (x))^2 (1+tan^2 (x))

∫(1+2tan^2 (x) +tan^4 (x)) (1+tan^2 (x))
u=tan (x) du=sec^2 dx

i'm stuck now
 
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afcwestwarrior said:

Homework Statement



∫sec^6 t dt

Always remeber to put what you integrating with respect to.

I'll help you out a bit

\int sec^6(t) dt= \int sec^4(t)*sec^2(t) dt

Now use sec2=1+tan2 to find what sec4will be.
 
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