How Do You Isolate 'g' in the Equation s=ut+1/2at^2?

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To isolate 'g' in the equation s=ut+1/2at^2, the formula can be rearranged to g=2s/at^2. The conversion to the form y=mx involves using y=(2s/a)x(u/2), which helps in graphical representation. A graph plotting acceleration (m/s^2) against time (s) will yield a slope that represents 'g'. This approach allows for both calculation and visual confirmation of the value of gravitational acceleration. Understanding these conversions is crucial for accurate data analysis.
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As part of our data analysis, we need to find 'g' through a calculation and then back it up with graphical representation. Since I have 'u', 's' and 't', the choice of equation is rather simple: s=ut+1/2at^2. Then this needs to be converted so y=mx, it's by no means necessary, but I want to do it.

I got told that t^2= (2sy)/(ay)=(2/ay) x (sy) is the conversion for y=mx, yet I it doesn't seem right to me. I'm also not sure whether that value of 'y' is that graphical value of 'y', but it doesn't look like it to me.
 
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It's a bit confusing but if I'm understanding correctly, the equation you are looking for is s=ut+1/2at^2. To convert this equation to y=mx form you would use the following: y=(2s/a)x(u/2). This equation is useful for finding the value of 'g' (the acceleration due to gravity): g=2s/at^2. To graphically represent this equation, you can plot a graph of acceleration (in m/s^2) against time (in s). The slope of the line (m) will represent the value of 'g'.
 
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