phantom113
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I'm choosing an angle for a diffraction grating such that a particular wavelength λ is retroreflected (reflected back along incident path). The book that I'm looking through treats the blazed diffraction grating as a set of N slits. This results in the equation
I(θ)=[itex]\frac{I(0)}{N^{2}}(sinc(β)^{2})(\frac{sin(Nα)}{sin(α)})^{2}[/itex]
where β=(kb/2)sin(θ) and α=(ka/2)sin(θ) with b=length of slit and a=distance between center of two adjacent slits
k is the wavenumber(I think).
What I'm looking for is a kick in the right direction. I'm not sure how this equation helps me. I think there is something fundamental that I'm not understanding. Obviously I want the intensity to be maximized along retroreflected path. Any help would be great. Thank you.
I(θ)=[itex]\frac{I(0)}{N^{2}}(sinc(β)^{2})(\frac{sin(Nα)}{sin(α)})^{2}[/itex]
where β=(kb/2)sin(θ) and α=(ka/2)sin(θ) with b=length of slit and a=distance between center of two adjacent slits
k is the wavenumber(I think).
What I'm looking for is a kick in the right direction. I'm not sure how this equation helps me. I think there is something fundamental that I'm not understanding. Obviously I want the intensity to be maximized along retroreflected path. Any help would be great. Thank you.