How Do You Solve a 2nd Order Inhomogeneous ODE with Given Initial Conditions?

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1. Using the complementary function and particular integral method find the solutio of the differential equation.

d2y/dx^2 + 3 dy/dx +2y = 20cos2x

Which satisfies y(0) = 1 y'(0) = 0



Homework Equations





The Attempt at a Solution

 
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there are different ways to solve this differential equation.
I know you can solve it with the method of undetermined coefficients OR Variation of Parameters.
 
I have already found the complementary function to be:

y = Ae^(-t) + Be(-2t)

Im just not sure how to find the particular integral!
 
Try yp = Ccos(2x) + Dsin(2x) for your particular solution.

Minor note: The independent variable should be x, not t, since x is the independent variable in your differential equation.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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