How Do You Solve a Basic BJT Problem Using KVL?

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The discussion focuses on solving a basic BJT problem using Kirchhoff's Voltage Law (KVL). The user successfully calculated the emitter current (i_e) as -0.52mA but encountered difficulties determining the collector current (i_c) and relating Vce and Vcb in the CE and CB loops. Confusion arises regarding the transistor's operating mode, as it appears to be in cutoff despite current flow. Suggestions include assuming Ic equals Ie and reversing the polarity of the 15V supply to clarify the circuit's operation. The circuit configuration is noted to be unusual, indicating potential errors in the biasing setup.
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Homework Statement


bjt q5.png


Homework Equations


KVL

The Attempt at a Solution


Using KVL around BE loop
0-0.6-i_e*(30*10^3)-15=0
i_e=-0.52mA
However, I stuck when I tried to find i_c and use KVL around CE loop/ CB loop
For CE loop:
10-i_c*(15*10^3)-Vce-i_e*(30*10^3)-15=0
For CB loop:
10-i_c*(15*10^3)-Vcb=0
I got confused about how to relate Vce and Vcb. (here I guess it must be some kind of relationship that looks like Vbc-Vac=Vba)
Also, it seems like it is operating in cutoff mode (both Vc and Ve>Vb), however, there is current flowing around the loop. So what is the mode that the transistor is actually operating in?
Thank you!:confused:
 

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Circuit looks odd to me. Like common base configuration but the polarity of the emitter bias voltage is wrong ( should be -15v). Think the transistor is either off or they made a mistake?

Otherwise I would suggest you assume Ic=Ie.
 
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Yes, try reversing the polarity of the 15v supply.
 
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