How Do You Solve a Pre Calculus Problem with Congruent Sides and Diagonals?

AI Thread Summary
To solve the pre-calculus problem involving a quadrilateral with congruent sides and a diagonal of length 6, the goal is to find the value of x such that the area of the shaded region is 40% of the area of the unshaded region. The equation derived is x/(6-x) = 0.4, leading to the solution x = 1.71. The areas of the shaded and unshaded regions are represented as S1 and S2, respectively, and the relationship S1/S2 = 0.4 is key to solving the problem. The calculations confirm that the approach is correct, emphasizing the importance of understanding how the areas are derived. The final answer is x = 1.71.
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[SOLVED] Pre Calculus Homework Problem...Help!

1. Homework Statement

A quadrilateral has two pairs of congruent sides and a longer diagonal of length of 6, as shown. For what value of x will the area of the shaded region be 40% of the area of the unshaded region?


2. Homework Equations

x=.40(6-x)

3. The Attempt at a Solution

x=1.71
 

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the area of shaded region is S1 = x*a and of unshaded S2 = (6-x)a. You also know that S1/S2 = 0.4 . Now just solve the equation for x.
 
Pre Cal Hwk Problem: Answer

x(a)/(6-x)(a)= 0.4
The a's cancel out...so that leaves me with: x/(6-x)=0.4 x=2.4/1.4 x=1.71

Is my work correct?
 
It looks fine. The important thing is to realize where the areas came from.
 
Thanks for the help!
 
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