How Do You Solve a Vector Calculus Integral Over a Sphere?

AI Thread Summary
The discussion centers on evaluating the double integral of the vector field over the surface of a sphere. The user initially attempts to set up the integral using spherical coordinates but realizes they may have made a mistake by treating it as a triple integral instead of a double integral. Key points include the correct expression for the unit normal vector and the area element on the sphere's surface. The conversation highlights the importance of using appropriate integration techniques and the correct limits for spherical coordinates. Ultimately, the user seeks clarification on the correct approach to solving the integral explicitly.
Hoofbeat
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Anyone take a look at this vector calculus question for me:

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Q. If n is the uni normal to the surface S, evaluate Double Integral r.n dS over the surface of a sphere of radius 'a' centred at the origin.
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So I did:

r = (x,y,z)
Sphere: x^2 + y^2 + z^2 = a^2

let f = x^2 + y^2 + z^2

n = gradf / |grad f|

therefore n = (x,y,z)/a

n.r = a

Now how do I proceed with the integral? I thought it would just be

int(2pi->0) int (pi->0) int(a->0) a r.dr.d[theta].d[phi]

which gives the answer [pi]^2.[a]^3 which really doesn't look right! I think it's the actual integral I've made a mistake with! HELP! I HATE VECTOR CALCULUS [and I really need to learn to use latex!]
 
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Isnt n = \frac{2x,2y,2z}{|gradF|}?
 
Btw, I know that a simple way to solve my problem is just to use the fact that the surface area of the sphere is 4*pi*a^3, but I want to solve the integral explicitly (as practise). Have found my tutor's notes and she found the 'area element' to be a*sin^2*theta*d[theta]*d[phi] and thus carried out a double integral. Could someone explain this please?
 
whozum said:
Isnt n = \frac{2x,2y,2z}{|gradF|}?


Yes but the |gradF| on the bottom gives you a factor of 2, so it cancels :frown: Having found my tutor's notes I know that I'm doing fine up until the integral and I shouldn't be doing it as a triple integral, but rather a double integral as I've explained in my above post.
 
Theres a few spherical coordinate problems here including derivations that are explained pretty well.

http://tutorial.math.lamar.edu/AllBrowsers/2415/TISphericalCoords.asp
 
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thanks. they're still carrying out triple integrals though, whereas I should only be doing a double integral :s
 
I'd help you out but I don't have my calc 3 book to recall the specific steps in deriving spherical coordinates, but I am pretty sure spherical coordinates only works in triple integrals since it uses 3 parameters, p,theta,phi.

Im probably not the person to helping you with this. Sorry.
 
There is a section on any kind of integration on the left hand navigation menu if you want to look around yourself.

edit: http://tutorial.math.lamar.edu/AllBrowsers/2415/SurfaceIntegrals.asp
Example 2
 
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Hoofbeat said:
Anyone take a look at this vector calculus question for me:

=====
Q. If n is the uni normal to the surface S, evaluate Double Integral r.n dS over the surface of a sphere of radius 'a' centred at the origin.
=====

So I did:

r = (x,y,z)
Sphere: x^2 + y^2 + z^2 = a^2

let f = x^2 + y^2 + z^2

n = gradf / |grad f|

therefore n = (x,y,z)/a

n.r = a

Now how do I proceed with the integral? I thought it would just be

int(2pi->0) int (pi->0) int(a->0) a r.dr.d[theta].d[phi]

which gives the answer [pi]^2.[a]^3 which really doesn't look right! I think it's the actual integral I've made a mistake with! HELP! I HATE VECTOR CALCULUS [and I really need to learn to use latex!]
SOLUTION HINTS:
Problem requires evaluation of {∫ ∫ r⋅dA} over Surface of Sphere of Radius "a":
The Unit Area normal element on the Sphere's surface is given by:
dA = r2sin(φ)⋅dθ⋅dφ⋅r/|r|
::: ⇒ ∫ ∫ r⋅dA = ∫ ∫ r⋅r2sin(φ)⋅dθ⋅dφ⋅r/|r| =
= ∫ ∫ r3sin(φ)⋅dθ⋅dφ = ?
The above Double Integral should be evaluated at constant (r = a) for integration limits {0 ≤ θ ≤ 2*π} and {0 ≤ φ ≤ π}.

For more info, see Equation #14 at:
http://mathworld.wolfram.com/SphericalCoordinates.html


~~
 
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