How Do You Solve Complex Torque Problems in Physics?

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The discussion revolves around solving a complex torque problem involving pulleys and forces. Key concepts include the relationship between torque, moment of inertia, and angular acceleration, emphasizing that for the system to remain static, the torques must be equal and opposite. Participants highlight the importance of free body diagrams (FBDs) to visualize forces and apply Newton's Second Law effectively. Clarification is sought on the correct radius to use in torque calculations for the pulleys, with the understanding that belts transmit force rather than torque. Ultimately, the original poster resolves their confusion with the assistance of the forum.
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Trying to describe this problem in words would be rather tedious, dull and very difficult for all involved, so without further ado:

http://portfolio.iu.edu/whoblitz/problem.PNG

My problem: I don't have a clue. I know torque is basically radius (lever arm) times force and that it is also moment of inertia times angular acceleration. I realize there are a lot of "PLZ DO MY HOMEWARKZ!11one" questions here, but I am really at a loss.

I don't expect anyone to do my homework, I just need a path to follow.
 
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First think about what have to be equal in order for that pulley to stay still (omega = 0 rad/s, alpha = 0 rad/s^2)? And then work you problem form there.
 
So is it ok to assume the two torques would have to be equal?
 
As is frequently the case with problems like this, a free body diagram is an excellent place to start. When you're dealing with the pulleys - in particular with the pulley attached to the truck - remember that each line of the rope provides an independent pull on the pulley.

Be sure you list all of the forces involved, remember that the pulley by itself does nothing except redirect the tensions, and remember Newton's Second Law. You should be fine.
 
willworkforfood said:
So is it ok to assume the two torques would have to be equal?
Newton's second law, ΣM = ΣI*α, if alpha is equal to 0, thus net moment is 0. Two torques have equal magnitude but opposite direction.

As Diane said, draw FBDs of both pulleys and use Newton's second Law (F=ma).
 
The problem as I have it now:

first pulley torque=second pulley torque
r*f=r*f
3*r*m*9.8=(r+.5*r)*2340*9.8*sin(30.6)

I am not sure if the radius on the second pulley's torque equation would simply be r/2 (2nd pulley radius) or the sum of the radii of the inner part of pulley 1 and pulley #2 r+r/2 as above.

Clarification requested if at all possible and is this setup right? Thanks again :approve:
 
The belts don't transmit torque, they transmit force - specifically, the tension in the belt/rope. The differing radii of the pulleys will cause that tension to give different torques. Does that make any sense?
 
edit:

Figured it out, thanks.
 
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