How Do You Solve the Supernode Equation Involving Node C?

  • Thread starter Thread starter noname1
  • Start date Start date
AI Thread Summary
The discussion focuses on solving a supernode equation involving node C, where the voltage at node C is established as 150 volts due to a connected battery. The equations provided include relationships between the voltages at nodes A, B, C, and D, with specific attention to the impact of resistors on these voltages. A participant points out an error related to node D, suggesting a correction to the third equation for accurate results. Final calculated values for the voltages are Va = 11.712, Vb = 111.712, Vc = 150, and Vd = -63.063. The conversation emphasizes the importance of correctly applying voltage constraints in circuit analysis.
noname1
Messages
131
Reaction score
0
I am trying to resolve this super node but i am having trouble with the equation, more specifically node c, this is where i got so far


5 = Va/20 +(Va - Vd)/10 + (Vb - Vc)/12.5
-10 = (Vd - Va)/10 + Vd/25
-Va + Vb = 100

please explain the c node equation
 

Attachments

  • scan0005.jpg
    scan0005.jpg
    22.2 KB · Views: 404
Physics news on Phys.org
Assuming the positive end of the 150 volt battery is connected to node C, then the equation is simply: Vc = 150
 
but don't we have to include the 12.5 resistor from node b to node c?
 
That resistor is taken care of by your first equation.

When you have a voltage source connected from ground to some node, you need a (constraint) equation that simply says that the voltage at (in this case) node C is 150 volts.

It's similar to your third equation.
 
i am getting an error on node d can anyone tell me what i am doing wrong, its the 3rd equation on the last process
 

Attachments

I think that equation should be:

-5Va + 7Vd = -500

For final answers, I get:

Va = 11.712
Vb = 111.712
Vc = 150
Vd = -63.063
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top