How Do You Solve These Challenging Physics B Problems?

  • Thread starter Thread starter 8parks11
  • Start date Start date
  • Tags Tags
    Hard Physics
AI Thread Summary
The discussion revolves around solving challenging physics problems involving tension in a cable supporting an elevator and calculating the minimum coefficient of friction for cartons in a truck. For the elevator, the correct tension calculations for constant speed and different accelerations were clarified, emphasizing that at constant speed, acceleration is zero. The minimum coefficient of friction required to prevent sliding cartons was initially thought to be 5 but needed further verification. Additionally, participants sought confirmation on the readings of a spring scale under varying weights, with specific values discussed for different mass scenarios. Overall, the thread highlights the importance of understanding fundamental physics concepts to solve these problems accurately.
8parks11
Messages
63
Reaction score
0
physics B problems :( hard hard

A single cable supports an 837-kg elevator car. What is the tension in the cable when the car is moving with a) constant speed, b) an upward acceleration of 3.21 m/s^2 and c) a downward acceleration of 3.21m/s^2

I'm not totally lost. Since the T is directed downward, I can derive from

F=ma
T+mg=ma
T=ma+mg (since g is negative)

so I thought T would be for
a)873(1)+837(9.8)
b) 873(3.21)+(873)(9.8)
c) 873(-3.21)+873(9.8)


is this correct?? if not someone please help me!





next question: A truck loaded with heavy cartons is forced to stop suddenly with a deceleration of 5.0m/s^2. Calculate the minimum coefficient of frcition between the cartons and the truck bed given that the cartons do not slide.


I thought it would just be 5. is this correct?





and last but not least


http://img216.imageshack.us/img216/5...caleid1.th.jpg
(ignore the mass of the scale btw)

what will the spring scale S in the middle read when
a) m1=1kg m2=1kg
b) m1=1.2kg m2=1kg

I thought it would be 1 for a) but that's not the answer.
b), I thought it would be 1.1

i did 1/2(m1+m2) but I don't think this is right
someone please confirm it!
thanks





thanks
 
Last edited by a moderator:
Physics news on Phys.org
8parks11 said:
A single cable supports an 837-kg elevator car. What is the tension in the cable when the car is moving with a) constant speed, b) an upward acceleration of 3.21 m/s^2 and c) a downward acceleration of 3.21m/s^2

I'm not totally lost. Since the T is directed downward, I can derive from

F=ma
T+mg=ma
T=ma+mg (since g is negative)

so I thought T would be for
a)873(1)+837(9.8)
b) 873(3.21)+(873)(9.8)
c) 873(-3.21)+873(9.8)


is this correct?? if not someone please help me!
a) If you're moving at a constant speed, then acceleration is 0, not 1.
b) and c) Correct.
 
so a) is just mg and b) is also correct?
 
answer

what will the spring scale S in the middle read when
a) m1=1kg m2=1kg

ok for this, the answer is 1.. kg? anyways its 1 something..


b) m1=1.2kg m2=1kg


ok how do I do this one?
I have no idea how
 
ccan someone confirm that
b) 1.1?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top