How Do You Solve Trig Identities Using Basic Trigonometric Equations?

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The discussion focuses on solving the trigonometric identity (1 + cosθ) / (1 - cosθ) = (1 + secθ) / (secθ - 1) using basic trigonometric identities. Participants emphasize the importance of recognizing that cosθ is the reciprocal of secθ, which simplifies the problem significantly. By manipulating the right side of the equation with reciprocal identities, the solution is reached efficiently. The conversation highlights the challenges of learning trigonometric identities and the value of practice and guidance from teachers. Overall, mastering these identities requires time and effort, but understanding the relationships between functions can make the process easier.
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Homework Statement



(1 + cosθ) / (1 - cosθ) = (1 + secθ) / (secθ - 1)

Homework Equations



using only the quotient identities, pythagorean identities, and reciprocal identities

The Attempt at a Solution



didnt know where to start...
 
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lol Mark44.

Key word is reciprocal identity, and this should be obvious since cos\theta is the reciprocal of sec\theta and vice versa.
 
kk got it.

RS
=(1 + secθ) / (secθ - 1)
=(1 + 1/cosθ) / (1/cosθ - 1)
=([cosθ+1] / cosθ) / ([1-cosθ] / cosθ)
=[(cosθ+1)(cosθ)] / [(1-cosθ)(cosθ)]
cancel cosθ
=(1 + cosθ) / (1 - cosθ)
 
oh wow, all these question are so easy now, thanks for the advice about the reciprocal.
 
No problem :smile:

I remember starting off with trig identities... I would have to say that was the hardest and most stressful topic to learn. If you don't have someone like your teacher to help you out with those, you can get lost in a question for hours! Well, at least that's what me and a few of my friends did.

It all comes to you eventually with much practice on this topic though. Good luck.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Essentially I just have this problem that I'm stuck on, on a sheet about complex numbers: Show that, for ##|r|<1,## $$1+r\cos(x)+r^2\cos(2x)+r^3\cos(3x)...=\frac{1-r\cos(x)}{1-2r\cos(x)+r^2}$$ My first thought was to express it as a geometric series, where the real part of the sum of the series would be the series you see above: $$1+re^{ix}+r^2e^{2ix}+r^3e^{3ix}...$$ The sum of this series is just: $$\frac{(re^{ix})^n-1}{re^{ix} - 1}$$ I'm having some trouble trying to figure out what to...

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