- #1
chemic_23
- 44
- 0
Homework Statement
Homework Equations
how do you square cosB?
How Do You Square Cosine B?
- Thread starter chemic_23
- Start date
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- Tags
- Square
AI Thread Summary
To square cosB, treat it like any real number, applying the squaring operation directly. The discussion highlights the need for clarification on whether the goal is to solve an equation involving cosB, as there are infinite solutions possible. A user seeks help on understanding how to square cosB in the context of a function involving constants. The example provided illustrates how to expand a squared expression. Overall, the conversation emphasizes the importance of clear questions for effective assistance in mathematical problems.
how do you square cosB?
- #2
Galadirith
- 107
- 0
Hi chemic_23, well you haven't really asked a question. In answer to you how do you square cos\beta (i assume that's what you meant) you can square it like any other number as \textbf{cos\beta} will be a real number if beta is a real number. Is you question find the solutions to this equation, because there are an infinite number of them?
If you could clarify you question then I am sure you'll find the help you need :D
- #3
chemic_23
- 44
- 0
I'm trying to understand this part of solution
but I don't have any idea on how to square the cosB... It just came out with no detailed solution... please help
- #4
salman213
- 301
- 1
if you have f(l) = (x + y) / z where x,y,z are constants
remember you can always change that to
x /z + y/z
and then what would be f^2 (l)
(x /z + y/z)^2 = (x /z + y/z)(x /z + y/z)
and you can expand that right?
- #5
chemic_23
- 44
- 0
thanks:)
Neglect gravity other than that of water; neglect friction.
F1=ρgsh=1000*10*1*(1+4)=50000 N;
F1=ρgsh=1000*10*0.1*4=4000 N;
F3=50000-4000=46000 N?
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system
$$M(t) = M_{C} + m(t)$$
$$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$
$$P_i = Mv + u \, dm$$
$$P_f = (M + dm)(v + dv)$$
$$\Delta P = M \, dv + (v - u) \, dm$$
$$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$
$$F = u \frac{dm}{dt} = \rho A u^2$$
from conservation of momentum , the cannon recoils with the same force which it applies.
$$\quad \frac{dm}{dt}...
I was told forces are vectors so they can be divided into x and y components, but what about the normal force or the force of static friction? do you divide those into x and y components if say you had a block that was lying on an angled surface?
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