orthovector
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how do you take take this integral?
\int_{0}^{r} x^2 e^{-2x} dx
\int_{0}^{r} x^2 e^{-2x} dx
gabbagabbahey said:Use integration by parts (twice)...the derivatives of x^2 are easy to find, and likewise for the antiderivative of e^{-2x}dx
ice109 said:whats the upper limit? if it's infinity answer is 1/8
orthovector said:do you know how this integral turns into
\frac {N!}{a^{N + 1}} if I take the integral from 0 to infinity? N = 2 and a = 2
gabbagabbahey said:If N=2 and a=2, then \frac {N!}{a^{N + 1}}=\frac {2!}{2^{2 + 1}}=\frac{1}{4} which is what you should be getting using by parts.
Are you getting something different?
orthovector said:I was trying to derive the general expression
\int_{0}^{\infty} x^n e^{-ax} dx = \frac{n!}{a^{n+1}}
how is this so?