How Does a Falling Metal Bar Generate Electricity in a Magnetic Field?

AI Thread Summary
A 50 g metal bar falls in a 0.060 T magnetic field while connected to a 1.0 Ohm resistor, generating electricity as it moves. The discussion focuses on calculating the terminal speed of the bar, which occurs when the velocity stabilizes and the acceleration becomes zero. At terminal velocity, the net force acting on the bar is zero, indicating that the gravitational force is balanced by the magnetic force. The key equations relate current, motional emf, resistance, velocity, length, and magnetic field. Understanding these concepts is crucial for solving the problem of the bar's motion and the electricity generated.
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1. A 50 g horizontal metal bar, 12 cm long, is free to slide up and down between two tall, vertical metal rods. A 0.060 T magnetic field is directed perpendicular to the plane of the rods. The bar is raised to near the top of the rods, and a 1.0 Ohm resistor is connected across the two rods at the top. Then the bar is dropped. What is the terminal speed at which the bar falls? Ignore air resistance.

2. I= ε/R= (vlB)/R

I is current, ε is motional emf, R is resistance, v is velocity, l is length, B is magnetic field.




3. I don't even know where to start. I know that R= 1.0, l= .12 m, B= 0.060 T. What do I do with the 50 g?
 
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I will start you off by asking and answering the first question. You have to answer the rest to get going.

Q0. What does "terminal velocity" mean?
Ans. That the velocity reaches a final value that stays the same.

Q1. If the velocity stays the same what is the value of the acceleration?
Q2. If the acceleration has that value what does that say about the net force on the bar?
Q3. How many forces act on the bar when it reaches terminal velocity?
Q4. Given all your previous answers, what is the relation linking the forces acting on the bar?
 
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