How Does a Pulley System Help Rescue a Cat from a Tree?

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Homework Help Overview

The problem involves a pulley system designed to rescue a cat from a tree, where the forces acting on a person and a seat are analyzed. The context includes calculating acceleration and the force exerted by the seat while considering the tension in the rope.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of mass and combined forces, questioning the tension in the rope and how it relates to the system's dynamics. There are attempts to clarify the forces acting on the person and the seat as a single system.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the forces involved. Some guidance has been offered regarding the number of rope segments affecting the system, leading to further questions about the mechanics of the pulley setup.

Contextual Notes

Participants are working within the constraints of a homework problem, focusing on the assumptions related to the forces acting on the system and the implications of the pulley configuration.

katie beisel
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Homework Statement



A cat is stuck in a tree. You are designated with the job to get it out, yet you do not want to climb the tree, because you may get stuck as well. Instead you set up a pulley system. A rope (consider it massless) runs from the seat you sit on over an ideal pulley and then to your hand. You pull on the loose end of the rope with a force of 348 N. You weigh 612 N and the seat you sit on weighs 16.0 N. (a) What is your acceleration? (b) What force does the seat exert on you?

Homework Equations


F=ma
t - mg = ma

The Attempt at a Solution


ok so i found the mass to be 64.2 kg
the combined force weight is 628 N
i thought the tension would be 348 N but I'm not getting the right answer with that
 
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katie beisel said:
i thought the tension would be 348 N but I'm not getting the right answer with that
That is the tension in the rope.

katie beisel said:
t - mg = ma
Careful here. The rope pulls on the person and on the seat.

(Hint: For part a, treat the person+seat as a single system. What forces act?)
 
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Doc Al said:
That is the tension in the rope.Careful here. The rope pulls on the person and on the seat.

(Hint: For part a, treat the person+seat as a single system. What forces act?)
i did that and i got -4.5 but the answer should be 1.06
 
katie beisel said:
i did that and i got -4.5 but the answer should be 1.06
Show what you did. What forces act on "person+seat"?
 
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Doc Al said:
Show what you did. What forces act on "person+seat"?
well they have a combined force weight of 628 N so 348 N - 628 N = 64.1 (i messed up the first time)a
which equals -4.3
 
katie beisel said:
well they have a combined force weight of 628 N so 348 N - 628 N = 64.1 (i messed up the first time)a
which equals -4.3
You have an upward force of only 348 N. But how many rope segments pull up on the system?
 
Doc Al said:
You have an upward force of only 348 N. But how many rope segments pull up on the system?
one
 
katie beisel said:
one
Nope. The rope pulls up twice. Once on the person; once on the seat.
 
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Doc Al said:
Nope. The rope pulls up twice. Once on the person; once on the seat.
ok doubling the force tension gives me the right answer but I'm confused why that is. I don't understand why it pulls up twice even though its only connected to the chair.
 
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katie beisel said:
I don't understand why it pulls up twice even though its only connected to the chair.
Ah, but it's not only connected to the chair. It's also connected to the person, who is pulling up on one end of the rope. (One end connects to the seat; the other end, to the person.)

Try this: Draw an imaginary box around the "person + seat". How many rope segments connect to that box?
 

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