How Does Adiabatic Expansion Affect an Ideal Gas in a Closed Cycle?

AI Thread Summary
The discussion focuses on the behavior of a diatomic ideal gas undergoing a closed cycle involving adiabatic expansion. Initially at 1.00 atm and 300 K, the gas's pressure is tripled at constant volume before expanding adiabatically back to its original pressure. The participants calculate the volume after adiabatic expansion as 8.77 L and the temperature at the start of the expansion as 900 K, while clarifying that the temperature at the end of the cycle remains 300 K due to the isobaric compression. The net work done on the gas can be determined using the First Law of Thermodynamics, as the gas returns to its original state, resulting in zero change in internal energy. The cycle is confirmed to be quasi-static.
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Homework Statement


A 4.00-L sample of a diatomic ideal gas with specific heat
ratio 1.40, confined to a cylinder, is carried through a
closed cycle. The gas is initially at 1.00 atm and at 300 K.
First, its pressure is tripled under constant volume.
Then, it expands adiabatically to its original pressure.
Finally, the gas is compressed isobarically to its original
volume. (a) Draw a PV diagram of this cycle. (b) Determine
the volume of the gas at the end of the adiabatic
expansion. (c) Find the temperature of the gas at the
start of the adiabatic expansion. (d) Find the temperature
at the end of the cycle. (e) What was the net work done on the gas for this cycle?

Homework Equations





The Attempt at a Solution


Part A is a graph of a typical adiabatic expansion. Part B I used PV^γ is constant and found V=8.77 L. Part C I used PV = nRT and got 900K.

I am stuck on part D, I know it should be 300 K, but I want to know why the equation TV^(γ-1) = constant isn't working. Lastly for part E, I don't know how to find the area under the curve without P as a function of V.
 
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Woopydalan said:

The Attempt at a Solution


Part A is a graph of a typical adiabatic expansion. Part B I used PV^γ is constant and found V=8.77 L. Part C I used PV = nRT and got 900K.

Correct!

Woopydalan said:
I am stuck on part D, I know it should be 300 K, but I want to know why the equation TV^(γ-1) = constant isn't working.
that equation gives the temperature at the end of the adiabatic expansion. It is not the end of the cycle: You have one isobaric compression left.

Woopydalan said:
Lastly for part E, I don't know how to find the area under the curve without P as a function of V.

No need to integrate. It is a cycle, the gas returns back to its original state, so the change of internal energy is zero. According to the First Law, the heat Q and W, the work done on the gas, add up to zero. You can calculate the heat exchange for each process: It is a diatomic gas, what are Cv and Cp? You also can determine the amount of gas.

ehild
 
Woopydalan said:

Homework Statement


A 4.00-L sample of a diatomic ideal gas with specific heat
ratio 1.40, confined to a cylinder, is carried through a
closed cycle. The gas is initially at 1.00 atm and at 300 K.
First, its pressure is tripled under constant volume.
Then, it expands adiabatically to its original pressure.
Finally, the gas is compressed isobarically to its original
volume. (a) Draw a PV diagram of this cycle. (b) Determine
the volume of the gas at the end of the adiabatic
expansion. (c) Find the temperature of the gas at the
start of the adiabatic expansion. (d) Find the temperature
at the end of the cycle. (e) What was the net work done on the gas for this cycle?
Is the adiabatic expansion quasi-static?

AM
 
Thanks guys!

I completely overlooked that it was asking for the temperature at the original spot...I was thinking at the end of the adiabatic expansion.

I'll give part E a try.

Yes it is quasi-static.
 
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