How Does Angular Velocity Change After Inelastic Collision?

AI Thread Summary
In an inelastic collision involving two equal masses, the initial linear momentum must be conserved, leading to the equation m1*v1i = (m1 + m2)*vf, which simplifies to vf = v1i/2. The angular velocity (w) is then expressed as w = vf/r, where r is the radius of rotation. If the length of the bar is 1 meter, the correct angular velocity becomes w = v1i/2. The discussion highlights confusion about the role of a ball atop mass m2, which is assumed to be the axis of rotation, indicating that angular momentum conservation should be applied instead of linear momentum due to constraints on m2. Understanding the setup and constraints is crucial for solving the problem correctly.
Jalo
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Homework Statement



A mass m1 with speed v1i colides with a mass m2 of length 1m, initially at rest, and gets stuck with it.
(a) Express the angular velocity in functon of v1i. (m=m1=m2)


122m0z6.jpg


Homework Equations



w=v/r

The Attempt at a Solution



Since the collision is totally inelastic I can say
m1*vi1=(m1+m2)vf
Since all masses are equal I can say
vi1=2vf⇔vf=v1i/2
Since w=v/r
w=vf/r⇔w=0.5*v1i/0.5⇔w=v1i

This is wrong for some reason... Can anyone lead me in the correct way?

Thanks.
D.
 
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If the length of the bar is 1, then the radius of a circle that the bar makes as it rotates 360 degrees means r=1. Thus w= 0.5V1i/1 = V1i/2.
 
I don't quite understand the diagram. What's that ball like thing on top of m2? Is m2 fixed at some point?
 
Doc Al said:
I don't quite understand the diagram. What's that ball like thing on top of m2? Is m2 fixed at some point?

Doc Al has a great point. More explanation is needed. I just assumed the ball at the top of the bar was an axis of rotation, but I could be wrong.
 
It doesn't say nothing about the ball, so I'm pretty sure it's the axis of rotation
 
Jalo said:
It doesn't say nothing about the ball, so I'm pretty sure it's the axis of rotation
Assuming that m2 is constrained to rotate about that axis, you cannot apply conservation of linear momentum. (The axis will exert forces on m2.)

But what other quantity is conserved?
 
Angular momentum?
 
Jalo said:
Angular momentum?
Right!
 
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