How Does Atmospheric Pressure Affect Measurements in a Torricelli Barometer?

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Atmospheric pressure plays a crucial role in the functioning of a Torricelli barometer, as it influences the height of the mercury column. The pressure at point A in the barometer is determined by the weight of the mercury column, represented by the formula (p*g*h), but it must also account for the atmospheric pressure acting on the liquid. Pascal's law states that pressure in a fluid at rest acts equally in all directions, but this does not imply uniform pressure throughout the fluid, especially in the presence of gravity. In a gravitational field, pressure varies with depth, and the space above the mercury in the tube is a vacuum, known as a "Torricelli vacuum." Understanding these principles clarifies how atmospheric pressure affects measurements in a barometer.
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I have a question about Pascal law. Recenly I was studying and I found this image in my physics book - a copy of the barometer which Torricelli used in his experiment (this is a redraw):

Barometer.png


Where the blue thing is the fluid (mercury), while the black thing is the container.

According to my textbook, the pressure at point A is simply (p*g*h), the preasure caused by the fluid above it. However, why don't we also count the atmospheric pressure? Isn't it supossed to act in the entire fluid according to Pascal's law?

Thanks in advance!
 
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There are no atmospheric pressure in the tube - it is closed tube and that white area at the top is vacuum. Therefore if you press liquid at the point B (atmospheric pressure), liquid will climb the tube at point A due to Pascal's law, until it counter weights the pressure;( here p*g*h is a weight of liquid in the tube).
 
Hi Peter:

The barometer is giving you information to tell you what the value of the unknown atmospheric pressure P is. See

Regards,
Buzz
 
A common misconception is that Pascal's law states that in a fluid at rest, pressure is transmitted throughout the fluid uniformly. This is not correct. Pascal's law actually states that at a particular position within a fluid at rest, the pressure acts the same in all directions (i.e., it is isotropic). This says nothing about how it varies from position to position.
 
Chestemiller, your comment surprises me! It appears my textbook has made a mistake with it's definition of Pascal's law! So, when is pressure transmitted though a fluid uniformly? And does this really have nothing to do with Pascal's law (what I mean is, do the special cases where pressure transmission is uniform follow from Pascal's law)?

(Sorry if some of these questions are unclear. English is a second language for me!)

Thanks for answers!
 
Peter Dimitrov said:
Chestemiller, your comment surprises me! It appears my textbook has made a mistake with it's definition of Pascal's law! So, when is pressure transmitted though a fluid uniformly? And does this really have nothing to do with Pascal's law (what I mean is, do the special cases where pressure transmission is uniform follow from Pascal's law)?

(Sorry if some of these questions are unclear. English is a second language for me!)

Thanks for answers!
In a gravitational field (i.e., with gravity), pressure varies with depth. So it is not uniform throughout the fluid. Pressure is transmitted uniformly throughout a fluid only if the fluid is in static equilibrium and there is no gravity. As I learned it, Pascal's law says only that, at a given spatial location in a fluid, pressure acts identically in all directions. That means that, if I place a tiny surface at an arbitrary location in a fluid that is in static equilibrium, the force per unit area is independent of the orientation of the surface, and acts perpendicular to the surface.
 
Peter Dimitrov said:
I have a question about Pascal law. Recenly I was studying and I found this image in my physics book - a copy of the barometer which Torricelli used in his experiment (this is a redraw):

View attachment 94518

Where the blue thing is the fluid (mercury), while the black thing is the container.

According to my textbook, the pressure at point A is simply (p*g*h), the preasure caused by the fluid above it. However, why don't we also count the atmospheric pressure? Isn't it supossed to act in the entire fluid according to Pascal's law?

Thanks in advance!

there is mercury vapour above the liquid in the tube, the pressure at A is hρg + saturated pressure of mercury at the prevailing temperature.
The space above the mercury is called a 'torrecelli vacuum'
 
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