How Does Dimensional Analysis Explain Standing Waves on a String?

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Dimensional analysis is used to determine the unknown exponents in the equation relating wavelength (lambda), wave speed (v), tension (T), and density (p). The analysis requires understanding the units of each variable: lambda is in meters, v in meters per second, T in Newtons, and p in kilograms per cubic meter. By equating the units on both sides of the equation, the exponents l, m, and n are found to be l = -1/2, m = -1, and n = 1/2. This process ensures that the dimensions match, confirming the relationships between the physical quantities. Dimensional analysis is crucial for validating equations in physics.
Nb
Standing waves on a string lab:

Use the method of dimensional analysis to show that the unknown exponents in the equation below are:

l=-1/2
m=-1
n=/2


lamda = k ì^l ƒ^m T^n


I do not understand this at all, I am not exactly sure what I am suppose to do.
 
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Since the problem said "dimensional analysis", you are going to have to use the "dimensions" (i.e. the units for each quantity).

Certainly before anyone can help you with this you will need to tell us what each of those symbols represents:
What is k and in what units is it measured?
What is i and in what units is it measured?
What is f and in what units is it measured?
What is T and in what units is it measured?

And, of course, what is lambda and in what units is it measured?

(Not, "what is" in the sense of what number. What does it measure: length, frequency, time?)
 
Can you please explain?

Dimensional analysis is a method used to analyze the relationships between different physical quantities by looking at their units. In the equation given, we have the wavelength (lambda), the wave speed (v), the tension in the string (T), and the density of the string (p).

The unknown exponents, l, m, and n, represent the powers to which the physical quantities must be raised in order to have the same units on both sides of the equation. In other words, the units on the left side of the equation (wavelength) must be the same as the units on the right side of the equation (k, p, v, and T raised to some powers).

We can start by looking at the units of each physical quantity:

- Wavelength (lambda): meters (m)
- Wave speed (v): meters per second (m/s)
- Tension (T): Newtons (N)
- Density (p): kilograms per cubic meter (kg/m^3)

Now, we can look at the units on each side of the equation:

- Left side: meters (m)
- Right side: k ì^l ƒ^m T^n
- k: unknown unit
- ì: meters per second (m/s)
- ƒ: Newtons (N)
- T: kilograms per cubic meter (kg/m^3)

We can see that the units on the left side of the equation must be equal to the units on the right side. This means that the powers to which each quantity is raised must be such that the units cancel out and we are left with meters on both sides.

To find the unknown exponents, we can equate the powers of each unit on both sides of the equation:

- For meters (m): 1 = l
- For meters per second (m/s): 1 = -l
- For Newtons (N): 1 = -m
- For kilograms per cubic meter (kg/m^3): 1 = n

Solving for l, m, and n, we get:

- l = -1/2
- m = -1
- n = 1/2

This shows that the unknown exponents in the equation are l = -1/2, m = -1, and n = 1/2. This method of dimensional analysis helps us understand the relationship
 
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