How Does Doubling Frequency Affect Wavelength on a Constant Tension String?

AI Thread Summary
Doubling the frequency of a wave on a constant tension string results in halving the wavelength, as the wave speed remains constant due to unchanged tension. The relationship between frequency, wavelength, and wave speed is expressed as V = fλ, where V is wave speed, f is frequency, and λ is wavelength. The discussion clarifies that the teacher's comment about wavelength being constant may not apply in this context, as it pertains to traveling waves rather than standing waves. Participants agree that if frequency increases, the wavelength must decrease proportionally. Understanding this relationship is crucial for analyzing wave behavior on strings.
BizzPhizz
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Homework Statement


This is a communication question, no variables given:

Predict what happens to the wavelength of a wave on a
string when the frequency is doubled. Assume that the
tension in the string remains the same. Confirm your
prediction mathematically.


The Attempt at a Solution



All I know is that my teacher said in a string the wave length is constant, so help me...

Please also show it mathematically c:

Thanks,
BizzPhizz
 
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What do you know about harmonics in strings, and how their wave lengths in the string relate to the string length?
 
Okay, Don't rage at me if I get this wrong, but

V=λ/τ or V=∫λ

∫ being frequency, I know the question stated there was no change in tension of the string so velocity must be constant.

I don't know why my teacher said wave length in a string is constant, if that's the case there would be no pitch.

So I can come to a conclusion that if frequency doubles, wave length halves..
 
I think I may have misinterpreted the question before. I thought this was about standing waves, but now I suspect it's about traveling waves. If so, the scenario is that some source is generating waves at one end of the string, and its frequency is then doubled, right? (But note that if this is right then your teacher's remark about wave length being constant does not apply here.)
What you can be sure about is that the velocity of the waves is constant (because the tension is constant). That being all correct, I agree with your conclusion.
 
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